As per the problem
Jing spent
of her money on a pack of pens.
of her money on a pack of markers.
and
of her money on a pack of pencils.
Total fraction of money spent cab be given as below
Fraction of Money Spent =
Take the LCD of denominator, we get LCD of (3,2,8)=24
Fraction of Money Spent =

Answer:
< CFE = 40°
Step-by-step explanation:
To better understand the solution, see attachment for the diagram.
Given:
BC parallel to DE
Measure of Arc BD = 58°
Measure of Arc DE = 142°
First step: Draw a diameter that passes through the centre of the circle and name it. In this case, the diameter is line ST.
The line ST divides the arc BD and arc DE into half.
That is:
Arc SC = 1/2(arc BC) =1/2(58)
Arc SC = 29°
Arc TE = 1/2(arc DE) =1/2(142)
Arc TE = 71°
Arc SC + Arc CE + Arc TE = 180° (Sum of angles in a semicircle
29° + Arc CE + 71° = 180°
Arc CE + 100° = 180°
Arc CE = 180-100
Arc CE = 80°
Inscribed angle = 1/2(intercepted angle)
<CFE = 1/2(Arc CE )
<CFE = 1/2(80)
< CFE = 40°
Answer:
(A)
Step-by-step explanation:
Given the equations:

Substitution simply means replacing the variable y in the second equation with its equivalent x+3 from the first equation.
Substitution of y into
gives us:

The correct option is A.
Answer:
3.876943x10^9
7.317x10^-4
Step-by-step explanation:
3,876,943,000
Put the decimal at the end
3,876,943,000.
Move it so only 1 number is before the decimal
3.876943000
We moved it 9 places, so that is the exponent
We moved it to the left, so the exponent is positive
The three zeros at the end can be dropped because they are the last numbers to the right of the decimal
3.876943x10^9
0.0007317
Move it so only 1 number is before the decimal
00007.317
We moved it 4 places, so that is the exponent
We moved it to the right, so the exponent is negative
The four zeros at the left can be dropped because they are the last numbers to the left of the whole number
7.317x10^-4
The probability of the pointer lands on red(R) both spin =
Step-by-step explanation:
Given,
The number of parts = 6
The pointer is spun twice.
To find the probability of the pointer lands on red(R) both spin.
Formula
Probability of an event = number of required outcomes ÷ the total number of outcomes.
P(A and B) = P(A)×P(B)
Now,
For one spin,
A = RED comes.
For second spin,
B = RED comes
So,
P(A) =
and P(B) =
Then,
P(A and B) =
×
=
Hence, the probability of the pointer lands on red(R) both spin =