In this question, you are given the average cofactor mass per cell (77.91pg) and the total cells count(10^5 cells). You are asked how much cofactor that will be found from those cells(microgram= 10^6 picogram). Then the calculation would be:
Cofactor mass= cofactor per cell * cell count= 77.91pg/cell * 10^5 cells= 7.791 x 10^6pg
Then convert the picogram(pg) into microgram: 7.791x 10^6pg/ (10^6pg/microgram)= 7.791 microgram
The Lewis structure of Chloroacetate (H₂CClCO₂) is given below. In structure it is shown that carbon has a double bond with one oxygen atom and two single bonds with CH₂Cl and O⁻.
Formal Charge; Formal charge is caculated as,
Formal charge = # of valence e⁻ - [# of lone pair of e⁻ + 1/2 # of bonded e⁻]
Formal charge on Oxygen (Highlighted Red);Formal charge = 6 - [ 6 + 2/2]
Formal charge = 6 - [6 + 1]
Formal charge = 6 - [7]
Formal charge = -1
Answer:
3.1°C
Explanation:
Using freezing point depression expression:
ΔT = Kf×m×i
<em>Where ΔT is change in freezing point, Kf is freezing point depression constant (5.12°c×m⁻¹), m is molality of the solution and i is Van't Hoff factor constant (1 For I₂ because doesn't dissociate in benzene).</em>
Molality of 9.04g I₂ (Molar mass: 253.8g/mol) in 75.5g of benzene (0.0755kg) is:
9.04g ₓ (1mol / 253.8g) = 0.0356mol I₂ / 0.0755kg = 0.472m
Replacing in freezing point depression formula:
ΔT = 5.12°cm⁻¹×0.472m×1
ΔT = 2.4°C
As freezing point of benzene is 5.5°C, the new freezing point of the solution is:
5.5°C - 2.4°C =
<h3>3.1°C</h3>
<em />
Answer:
The answer is A (number 1)
Answer:


Explanation:
Hello,
In this case, we can compute the mole fraction of benzene by using the following formula:

Whereas n accounts for the moles of each substance, thus, we compute them by using molar mass of benzene and cyclohexane:

Thus, we compute the mole fraction:

Next, for the molality, we define it as:

Whereas we also use the moles of benzene but rather than the moles of cyclohexane, its mass in kilograms (0.08074 kg), thus, we obtain:

Or just 0.990 m in molal units (mol/kg).
Best regards.