Answer:
Non-polar compounds:
,
, 
Polar compounds:
, 
Explanation:
For this question, we must start with the <u>Lewis structure</u> for each molecule and then we can do their respective analysis:
-) 
In this case, we have 4 equal atoms attached to the central atom. Therefore, we have the <u>same magnitude</u> of electronegativity. Chlorine atoms have <u>different and opposite directions.</u> Therefore due to the orientation the dipole moments cancel and the <u>net dipole moment will be zero</u> and the molecule will be non-polar.
-) 
In this case, we have a linear structure in which the magnitude of the dipole moment is the same, but the direction is the <u>opposite</u>. Therefore the dipole moments are canceled and the molecule will be <u>non-polar</u>.
-) 
In this case, we also have a linear structure in which the magnitude of the dipole moment is the same, but the direction is the <u>opposite</u>. Therefore the dipole moments are canceled and the molecule will be <u>non-polar</u>.
-) 
For this molecule, we have a <u>different atom</u>. The hydrogen atom, therefore the magnitude of one of the atoms attached to the central atom is different and the magnitude of the <u>net dipole moment will be different from zero</u> and the molecule will be <u>polar</u>.
-) 
For this molecule, due to the structure of the molecule, the dipole moments of oxygens <u>will not have a totally opposite configuration</u>. Therefore, the net dipole moment will be different from zero and the molecule will be <u>polar</u>.
See figure 1 to further explanations
I hope it helps!
Molarity = number of mole of substance(n) / volume of solution (V).
n(CaCl2) = mass (CaCl2)/M(CaCl2)
M(CaCl2) = 40+2*35.5 = 111 g/mol
n(CaCl2) =39.5 g CaCl2*1 mol/111g
0.250 M = 39.5 g CaCl2*1 mol/111g*volume of solution (V).
volume of solution (V) = 39.5 g CaCl2*1 mol/(0.250 M*111g) = 1.42 L
Answer:
The adjustable legs and the table of sand.
<em>Note:The question is incomplete. The complete question is given below.</em>
Using Models to Answer Questions About Systems
Armando’s class was looking at images of rivers formed by flowing water. Most of the rivers were wide and shallow, but one river was narrow and deep. Armando’s class thinks that this river is narrow and deep because:
- the hill that the water flowed down was very steep, or
- the sand grains that the water flowed through were very small.
Armando designed the model below to try to answer the question: Why is this river so narrow and deep?
Explanation:
The model designed by Armando will be helpful to answer the question because of the following features it possesses:
1. An adjustable leg- since one of the hypotheses put forward by the class to explain why the river was narrow and deep was that the hill that the water flowed down was very steep, the adjustable legs can be lowered or raised in order to make the slope shallower or steeper so that their hypothesis can be tested.
2. A table of sand- the table of sand serves as the streambed. By adjusting the size of the sand grains to be larger or smaller, the students will be able to to test their second hypothesis that the small size sand grains that the water flowed through was the reason for the river to be narrow and deep.
The results of their experiments will enable them to come to a conclusion.
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