Suppose you mix Na2SO4 and KCl solutions according to the given equation.
1 answer:
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Answer:
See explanation and image attached
Explanation:
When the carbocation is formed by the action of AlCl3 on the (CH3)3CCH2Cl, a primary carbocation is formed. The formation of the carbonation is followed by a 1,2-alkyl shift to give a tertiary carbocation which subsequently adds to the benzene ring as shown in the image attached to this answer.
Answer:
false thought ia ion of neon = clarity active
Explanation:
Answer:
Δ
Δ
Explanation:
Hello,
At the first state, the molar volume is:
The volume in both the second and third state:
Now, as it is about an adiabatic process, one remembers the following relationships:
- Next, for the aforesaid volumes and the first pressure, one computes the second pressure as:
- And the temperature:
- Q:
It is clear that the heat for the first process is 0 as it is adiabatic, but for the second one, it is computed as:
Then the total heat:
- The work for the first process is:
It is clear that the second process is isochoric, so the work here is zero, thus, the total work is:
- For the two processes, ΔU becomes the same value since the system returns to the initial temperature, so ΔU total is 0, thus, for each process, one's got:
- Finally, the total enthapy is also 0 due to same aforesaid reason, thus, each enthalpy is:
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