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HACTEHA [7]
2 years ago
4

A ballet dancer spins with 2.4 rev/s with her arms outstretched,when the moment of inertia about axis of rotation is 1 .With her

arms folded,the moment of inertia about the same axis becomes 0.61 . calculate the new rate of spin.
Physics
1 answer:
Scrat [10]2 years ago
8 0
The majestic ballerina spins faster when her MOI is smallest, which is when she folds up her arms. guessing at proportion, 1 MOI = 2.4 revs, 0.61 MOI = 2.4/0.61 revs which should be faster. It's a bit of a guess though, whilst I imagine "Swan Lake".
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An ocean liner is cruising at 10 meters/second and is about to approach a stationary ferryboat. A parcel is released from the oc
Afina-wow [57]
The parcel will undergo projectile motion, which means that it will have motion in both the horizontal and vertical direction.

First, we determine how long the parcel will fall using:

s = ut + 1/2 at²

where s will be the height, u is the initial vertical velocity of the parcel (0), t is the time of fall and a is the acceleration due to gravity. 

5.5 = (0)(t) + 1/2 (9.81)(t)²
t = 1.06 seconds

Now, we may use this time to determine the horizontal distance covered by the parcel by using:
distance = velocity * time

The horizontal velocity of the parcel will be equal to the horizontal velocity of the cruise liner.

Distance = 10 * 1.06
Distance = 10.6 meters

The boat should be 10.6 meters away horizontally from the point of release.
4 0
2 years ago
A figure skater rotating at 5.00 rad/s with arms extended has a moment of inertia of 2.25 kg·m2. If the arms are pulled in so t
Serggg [28]

a) 6.25 rad/s

The law of conservation of angular momentum states that the angular momentum must be conserved.

The angular momentum is given by:

L=I\omega

where

I is the moment of inertia

\omega is the angular speed

Since the angular momentum must be conserved, we can write

L_1 = L_2\\I_1 \omega_1 = I_2 \omega_2

where we have

I_1 = 2.25 kg m^2 is the initial moment of inertia

\omega_1 = 5.00 rad/s is the initial angular speed

I_2 = 2.25 kg m^2 is the final moment of inertia

\omega_2 is the final angular speed

Solving for \omega_2, we find

\omega_2 = \frac{I_1 \omega_1}{I_2}=\frac{(2.25 kg m^2)(5.00 rad/s)}{1.80 kg m^2}=6.25 rad/s

b) 28.1 J and 35.2 J

The rotational kinetic energy is given by

K=\frac{1}{2}I\omega^2

where

I is the moment of inertia

\omega is the angular speed

Applying the formula, we have:

- Initial kinetic energy:

K=\frac{1}{2}(2.25 kg m^2)(5.00 rad/s)^2=28.1 J

- Final kinetic energy:

K=\frac{1}{2}(1.80 kg m^2)(6.25 rad/s)^2=35.2 J

7 0
2 years ago
Submit Quiz
kkurt [141]

Explanation:

the question is unanswerable

7 0
2 years ago
A solid cylinder is radiating power. It has a length that is ten times its radius. It is cut into a number of smaller cylinders,
S_A_V [24]

Answer:

The total number of small cylinder = 7.

Explanation:

Lets take

Radius of the large cylinder = R

length = L

L = 10 R

The total area A = 2 π R² + π R L

The length of the small cylinder = l

The number of small cylinder = n

L = n l

The total area of small cylinders

A'=n (2 π R² + π R l)

As we know that emissive power given as

P = A ε σ T⁴

For large cylinder

P = A ε σ T⁴      -----------1

For small cylinders

P'=A' ε σ T⁴    ------2

From 1 and 2

Given that

P'= 2 P

A' ε σ T⁴ =2 A ε σ T⁴

A'=2 A       (All others are constant)

n (2 π R² + π R l) =(2 2 π R² + π R L)

n (2  R² +  R l) = (2  R² +  R L)

n(2R^2+R\times \dfrac{L}{n}) = 2(2R^2+RL)

L = 10 R

n(2R^2+R\times \dfrac{10R}{n}) =2 (2R^2+R\times 10R)

n(2+\dfrac{10}{n}) =2( 2+ 10)

2 n +10 = 2 x 12

2 n +10 = 24

2 n = 24 -10

2 n = 14

n = 7

The total number of small cylinder = 7.

3 0
2 years ago
A solution is oversaturated with solute. which could be done to decrease the oversaturation?
Grace [21]
<span>A solution is oversaturated with solute. The thing that could be done to decrease the oversaturation is to add more solvent in order to decrease the concentration of the solute. You can also increase the temperature to increase solubility of the solute. Hope this answers the question.</span>
4 0
2 years ago
Read 2 more answers
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