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Bas_tet [7]
2 years ago
5

Volume of water displaced = 0.175 L Mass g Density g/cm3 Hardness: = Determine the unknown mineral. Unknown mineral: 7​

Chemistry
1 answer:
erastovalidia [21]2 years ago
5 0

Answer:

Mass: 981.0 g

Density: 5.61 g/cm^3

Hardness: = 2.5 - 3

Unknown material: Chalcocite

Explanation:

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A sample of an unknown substance has a mass of .158 kg if 2,510 J of heat is required to heat the substance from 32°C to 61°C wh
ziro4ka [17]

Answer: 0.548J/g°C

Explanation:

Q = s × m × DeltaT

Q = Heat (J)

S = Specific Heat Capacity

M = mass (g)

DeltaT = Change in temperature (°C)

0.158Kg x 1000 = 158g

2.510J = s x 158g x (61°C-32°C)

2.510J/(158g x 29°C) = s

S = 0.54779.... J/g°C

S = 0.548 J/g°C

7 0
2 years ago
If 5.61 g of ammonium nitrate (NH4NO3) is dissolved in 155 mL of water to make an instant cold pack, what is the molarity of the
kifflom [539]

Answer:

0.452 M

Explanation:

Remember that to get molarity, you have to go thru an equation:

M=mol/V (in liters)

So...

5.61 g NH4NO3 x 1 mol NH4NO3/80.043 g

=0.0701 mol NH4NO3

Convert mL to L

=155--->0.155 L

Plug in and divide.

0.0701/0.155

=0.452 M

7 0
2 years ago
Use the conversion factor 1amu=6.66054 x 10^-24 to answer the following questions.. . a) 1.674 x 10^-24 g of neutrons is how man
Wewaii [24]
A.) The conversion factor is 1 amu = 1.66054 ^{-24}g

To know how many amu in 1.674x10^{-24}g grams of neutrons:
1.674x10^{-24}g ( \frac{x (amu) }{ 1.66054x10^{-24} g)}

=1.00811 amu

b.) The mass in grams of one lithium ion which has an atomic weight of 6.94 amu.

6.94 amu (\frac{6.66054 ^{-24} g}{1 amu}) = 4.62241x10 ^{23} g

c.) How many amu in 6.492x10^-23g potassium?

6.492x10^{-23}g ( \frac{x (amu) }{ 1.66054x10^{-24}g }) = 39.0957 amu


6 0
2 years ago
Read 2 more answers
**PLATO QUESTION, PLEASE ANSWER CORRECTLY, THANK YOU**
Nata [24]
The answers are the following that can be answered using the chart:

A. Which type of hurricane is expected to strike more frequently this century?
Category 4 + 5C. In general, will hurricanes likely become stronger or weaker this century?
Stronger, because there are more stronger ones thant he weaker ones that can result to hurricane.

E. Which types of hurricanes are expected to drop in frequency by more than 25% this century?
Categories 1, 2, 3


4 0
2 years ago
Cyclohexane has a freezing point of 6.50 ∘C and a Kf of 20.0 ∘C/m. What is the freezing point of a solution made by dissolving 0
ExtremeBDS [4]

Answer:

The freezing point will be 2.9^{0}C

Explanation:

The depression in freezing point is a colligative property.

It is related to molality as:

Depressioninfreezing point=K_{f}Xmolality

Where

Kf= 20\frac{^{0}C}{m}

the molality is calculated as:

molality=\frac{moles_{solute}}{mass_{solvent}}

moles=\frac{mass}{molarmass}=\frac{0.694}{154}=0.0045mol

massofcyclohexane=25g=0.025Kg

molarity=\frac{0.0045}{0.025}=0.18m

Depression in freezing point = 20X0.18=3.6^{0}C

The new freezing point = 6.5^{0}C-3.6^{0}C=2.9^{0}C

5 0
2 years ago
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