answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
svlad2 [7]
2 years ago
9

Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. How long will the bal

l be in the air before it lands? Round your answer to the nearest tenth. s How far will the football travel before it lands? Round your answer to the nearest tenth. m
Physics
2 answers:
RUDIKE [14]2 years ago
6 0

Answer:

1.2s for the first one

15.1m for the second one on time4learning

Explanation:

Step2247 [10]2 years ago
4 0

Answer:

T = 1.2 s

T = 15.1 m = 15 m

Explanation:

This is a case of projectile motion:

TOTAL TIME OF FLIGHT:

The formula for total time of flight in projectile motion is:

T = 2 V₀ Sinθ/g

where,

T = Total Time of Flight = ?

V₀ = Launch Speed = 13.9 m/s

θ = Launch Angle = 25°

g = 9.8 m/s²

Therefore,

T = (2)(13.9 m/s)(Sin 25°)/(9.8 m/s²)

<u>T = 1.2 s</u>

<u></u>

RANGE OF BALL:

The formula for range in projectile motion is:

R = V₀² Sin2θ/g

where,

R = Horizontal Distance Covered by ball = ?

Therefore,

T = (13.9 m/s)²(Sin 2*25°)/(9.8 m/s²)

<u>T = 15.1 m = 15 m</u>

You might be interested in
Ronald likes to use his erector set more than anything else.
Rashid [163]
C: Foreclosure. People in identity foreclosure have committed to an identity too soon. Often they have simply adopted the identity of a parent, close relative or respected friend.
5 0
2 years ago
Read 2 more answers
A basketball with mass of 0.8 kg is moving to the right with velocity 6 m/s and hits a volleyball with mass of 0.6 kg that stays
IceJOKER [234]

Answer:

26.67 m/s

Explanation:

From the law of conservation of linear momentum, the initial sum of momentum equals the final sum.

p=mv where p is momentum, m is the mass of object and v is the speed of the object

Initial momentum

The initial momentum will be that of basketball and volleyball, Since basketball is initially at rest, its initial velocity is zero

p_i= m_bv_b+m_vv_v=8*6+0.6*0=48 Kg.m/s

Final momentum

p_f= m_bv_b+m_vv_v=8*4+0.6*v_v=32+0.6v Kg.m/s\\32+0.6v_v=48\\0.6v=16\\v_v=16/0.6=26.66666667\approx 26.67 m/s

4 0
2 years ago
Bill leaves his 60 W desk lamp on every day, including weekends, for eight hours. After one month (30 days), how much total ener
maxonik [38]

' W ' is the symbol for 'Watt' ... the unit of power equal to 1 joule/second.

That's all the physics we need to know to answer this question.
The rest is just arithmetic.

(60 joules/sec) · (30 days) · (8 hours/day) · (3600 sec/hour)

= (60 · 30 · 8 · 3600) (joule · day · hour · sec) / (sec · day · hour)

= 51,840,000 joules
__________________________________

Wait a minute !  Hold up !  Hee haw !  Whoa ! 
Excuse me.  That will never do.
I see they want the answer in units of kilowatt-hours (kWh).
In that case, it's

(60 watts) · (30 days) · (8 hours/day) · (1 kW/1,000 watts)

= (60 · 30 · 8 · 1 / 1,000) (watt · day · hour · kW / day · watt)

= 14.4 kW·hour

Rounded to the nearest whole number:

14 kWh

7 0
2 years ago
a fixed mass of a n ideal gas is heated from 50 to 80C at a constant pressure at 1 atm and again at a constant pressure of 3 atm
vitfil [10]

Answer:

The energy required is same for both cases since specific heat capacity (Cp) does not vary with pressure.

Explanation:

Given;

initial temperature, t₁ = 50 °C

final temperature, t₂ = 80 °C

Change in temperature, ΔT =80 °C - 50 °C = 30 °C

Pressure for case 1 = 1 atm

Pressure for case 2 = 3 atm

Energy required in both cases is given;

Q = M*C_p*\delta T

where;

Cp is specific heat capacity, which varies only with temperature and not with pressure.

Therefore, the energy required is same for both cases since specific heat capacity (Cp) does not vary with pressure.

8 0
2 years ago
For each property listed, identify the type of element it describes. Very good electrical conductivity: Amphoteric, able to form
kow [346]

The elements that is very good in electrical conductivity are gold and copper: elements that is amphoteric are copper, zinc, tin, lead, aluminum and beryllium: elements that is gaseous at room temperature are hydrogen, nitrogen, oxygen, fluorine and chlorine: elements that is solid at room temperature are all metal except mercury and perhaps some unseen radioactive elements. Lastly, elements that is brittle are hydrogen, carbon, nitrogen, oxygen, phosphorus, sulfur and selenium

4 0
2 years ago
Read 2 more answers
Other questions:
  • _____ discovered that light also showed properties commonly found in waves.
    8·2 answers
  • Which of the following best describes the dependant variable?
    13·1 answer
  • A flashlight beam makes an angle of 60 degrees with the surface of the water before it enters the water. in the water what angle
    11·1 answer
  • Which of the following expressions will have units of kg⋅m/s2? Select all that apply, where x is position, v is velocity, m is m
    10·1 answer
  • Rock X is released from rest at the top of a cliff that is on Earth. A short time later, Rock Y is released from rest from the s
    13·1 answer
  • Three balls of equal mass are fired simultaneously with equal speeds from the same height h above the ground. Ball 1 is fired st
    7·1 answer
  • Suppose that you have left a 200-mL cup of coffee sitting until it has cooled to 30∘C , which you find totally unacceptable. You
    8·1 answer
  • 3. A 75kg man sits at one end of a uniform seesaw pivoted at its center, and his 24kg son sits at the
    11·1 answer
  • You are using a lightweight rope to pull a sled along level ground. The sled weighs 485 N, the coefficient of kinetic friction b
    11·1 answer
  • Feng and Isaac are riding on a merry-ground. Feng rides on a horse at the outer rim of the circular platform, twice as far from
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!