Answer:
The velocity of the boy is 0.11 m/s to the right.
The velocity of the girl is 0.13 m/s to the left.
Explanation:
Hi there!
The momentum of the system is conserved. That means that the initial momentum is equal to the final momentum (after throwing the ice ball for the boy and after catching the ball for the girl).
Let´s calculate the momentum of the system boy-ball:
The equation of the momentum is the following:
p = m · v
Where:
p = momentum.
m = mass of the object.
v = velocity.
Initially, the ball and the boy are at rest, so that the momentum of the system boy-ball is zero:
initial momentum = mib · vib + mb · vb
Where:
mib = mass of the ice ball.
vib = velocity of the ice ball.
mb =mass of the boy.
vb = velocity of the boy.
The initial momentum is zero because both velocities are zero.
After throwing the ball, the momentum of the system will be:
final momentum = mib · vib + mb · vb
final momentum = 0.75 kg · (- 6.2 m/s) + 43 kg · vb (Let´s consider the left as negative).
Since final momentum = initial momentum
0 kg · m/s =- 4.65 kg · m/s + 43 kg · vb
Solving for vb:
4.65 kg · m/s/43 kg = vb
vb = 0.11 m/s
The velocity of the boy after releasing the ball is 0.11 m/s. Since there is no friction, this velocity is constant. When the girl catches the ball, the velocity of the boy will be 0.11 m/s (to the right).
Now let´s do the same for the system girl-ball.
initial momentum = mg · vg + mib · vib
initial momentum = 35 kg · 0 m/s + 0.75 kg · (-6.2 m/s)
initial momentum = -4.65 kg · m/s
The final momentum is the momentum of the girl plus the ball:
final momentum = (mg + mb) · vgb
final momentum = (35 kg + 0.75 kg) · vgb
Since initial momentum = final momentum
-4.65 kg · m/s = (35 kg + 0.75 kg) · vgb
-4.65 kg · m/s / (35 kg + 0.75 kg) = vgb
vgb = -0.13 m/s
The velocity of the girl after catching the ball is -0.13 m/s (0.13 m/s to the left).
