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ioda
2 years ago
15

Mrs. Long keeps 25 books on her shelf for her students to read. Six of the books are non-fiction.

Mathematics
1 answer:
dedylja [7]2 years ago
4 0

Answer:24%

Step-by-step explanation:

6 divided by 25 is .24

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Billy had 55 stamps in his collection. billy’s older brother tommy had 73 stamps in his collection. how many stamps did the two
Rudik [331]
No.of stamps Billy had = 55

Number of stamps Billy's older brother had = 73

So total number of stamps two brother have together = 73 + 55
                                                                                     = 128

6 0
2 years ago
Solve for x: the quantity x plus fifty all over two equals thirteen times x
dusya [7]

Answer:

x = 2

Step-by-step explanation:

(x + 50)/2 = 13x, first multiply both sides by 2

x + 50 = 26x, next subtract x from both sides

50 = 25x, finally divide both sides by 25

2 = x

3 0
2 years ago
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An exponential function and a quadratic function are graphed below. Which of the following is true of the growth rate of the fun
aleksley [76]
Given an exponential function, say f(x), such that f(0) = 1 and f(1) = 2 and a quadratic finction, say g(x), such that g(0) = 0 and g(1) = 1.

The rate of change of a function f(x) over an interval
a \leq x \leq b
is given by
\frac{f(b)-f(a)}{b-a}

Thus, the rate of change (growth rate) of the exponential function, f(x) over the interval
0 \leq x \leq 1
is given by
\frac{f(1)-f(0)}{1-0} = \frac{2-1}{1} =1

Similarly, the rate of change (growth rate) of the quadratic function, g(x) over the interval
0 \leq x \leq 1
is given by
\frac{g(1)-g(0)}{1-0} = \frac{1-0}{1} =1

Therefore, the exponential grows at the same rate as the quadratic in the interval <span>0 \leq x \leq 1.</span>
3 0
2 years ago
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If a boy and a half can eat a hot dog and a half, in a minute and a half, how many hot dogs can six boys eat in six minutes?
Yanka [14]
SIx boys can eat seven (7) hotdogs in six (6) minutes.
3 0
2 years ago
Budget planners in two towns, Alphaville and Betaville, developed models to determine the budget surplus (in dollars) for a year
kramer

Answer:

(a)-3x^2+150x-10000

(b)-\$16,863,760,000

Step-by-step explanation:

Alphaville's Budget Surplus Model is -2x^2+ 500x

Betaville's Budget Surplus Model is x^2- 100x + 10000.

We want to determine the expression that shows how much greater Alphaville’s annual budget surplus is than Betaville’s for a particular amount of tax revenue.

  • To do this, we subtract Betaville's Model from Alphaville's model.

-2x^2+ 500x-(x^2- 100x + 10000)\\

Opening the brackets

-2x^2+ 500x-x^2+100x - 10000\\

Collect like terms and simplify

-2x^2-x^2+100x + 500x- 10000\\=-3x^2+150x-10000

The expression that shows how much greater Alphaville's Budget is:

-3x^2+150x-10000

(b) If the tax revenue that year in each town is $75,000

We want to evaluate the expression derived above when the tax revenue that year in each town is $75,000 i.e.at x=75000

-3x^2+150x-10000\\=-3(75000)^2+150(75000)-10000\\=-\$16,863,760,000

3 0
2 years ago
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