The correct option is d)greater input distance and a smaller force
Why?
We must remember that while a pulley has more rope sections, the force requiered to lift the load will be smaller, but the input distance required to lift the load will be greater.
Hence, for the problem, the correct option is d)greater input distance and a smaller force.
Have a nice day!
Answer:
we can say that with a smaller magnitude , the field will point is in same direction
Explanation:
we have given that
solenoid is filled with a diamagnetic material and with air, magnetic field pointing along its axis in the positive x direction
so in small magnitude, the field will point is in same direction
Let m = mass of asteroid y.
Because asteroid y has three times the mass of asteroid z, the mass of asteroid z is m/3.
Given:
F = 6.2x10⁸ N
d = 2100 km = 2.1x10⁶ m
Note that
G = 6.67408x10⁻¹¹ m³/(kg-s²)
The gravitational force between the asteroids is
F = (G*m*(m/3))/d² = (Gm²)/(3d²)
or
m² = (3Fd²)/G
= [(3*(6.2x10⁸ N)*(2.1x10⁶ m)²]/(6.67408x10⁻¹¹ m³/(kg-s²))
= 1.229x10³² kg²
m = 1.1086x10¹⁶ kg = 1.1x10¹⁶ kg (approx)
Answer: 1.1x10¹⁶ kg
Hey there!
The pressure under a liquid column can be , calculated using the following formula :
P = p x g x h
P atm = 1.013 x 10⁵ Pa
g = 9.8 m/s²
h = ?
h = P / ( p x g ) =
h= ( 1.013 x 10⁵ Pa ) / ( 900 x 9.8 ) =
h = ( 1.013 x 10⁵ ) / ( 8820 ) =
h = 11.48 m ≈ 11.50 m
Hope this helps!
Answer:
14.4 m/s
Explanation:
mass of Anna (Ma) = 68 kg
speed of Anna (Va) = 17 m/s
mass of SandraDay (Ms) = 76 kg
speed of SandraDay (Vs) = 12 m/s
We can find their speed (V) immediately after collision from the conservation of momentum where
(Ma x Va) + (Ms + Vs) = (Ma + Ms) x V
where V = speed immediately after collision
(68 x 17) + (76 + 12) = (68 + 76) x V
2068 = 144 V
V = 2068 / 144 = 14.4 m/s
