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Rama09 [41]
2 years ago
15

A projectile is launched at an angle of 60° from the horizontal and at a velocity of

Physics
1 answer:
gayaneshka [121]2 years ago
5 0

Answer:

60*12.0= 720 = v/60 * 12.0 squared which is 1,728

Explanation:

Horizontal velocity component: Vx = V * cos(α)

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What is the length of the x-component of the vector shown below?
jeka94

Answer:

D

Explanation:

7 0
2 years ago
Батискаф витримує тиск 60 МПа. Чи можна провести дослідження
Elanso [62]

1) Yes

2) 6.34\cdot 10^9 N

Explanation:

1)

To solve this part, we have to calculate the pressure at the depth of the batyscaphe, and compare it with the maximum pressure that it can withstand.

The pressure exerted by a column of fluid of height h is:

p=p_0+\rho g h

where

p_0 = 101,300 Pa is the atmospheric pressure

\rho is the fluid density

g=10 m/s^2 is the acceleration due to gravity

h is the height of the column of fluid

Here we have:

\rho=1030 kg/m^3 is the sea water density

h = 5440 m is the depth at which the bathyscaphe is located

Therefore, the pressure on it is

p=101,300+(1030)(10)(5440)=56.1\cdot 10^6 Pa = 56.1 MPa

Since the maximum pressure it can withstand is 60 MPa, then yes, the bathyscaphe can withstand it.

2)

Here we want to find the force exerted on the bathyscaphe.

The relationship between force and pressure on a surface is:

p=\frac{F}{A}

where

p is hte pressure

F is the force

A is the area of the surface

Here we have:

p=56.1\cdot 10^6 Pa is the pressure exerted

The bathyscaphe has a spherical surface of radius

r = 3 m

So its surface is:

A=4\pi r^2

Therefore, we can find the force exerted on it by re-arranging the previous equation:

F=pA=4\pi pr^2 = 4\pi (56.1\cdot 10^6)(3)^2=6.34\cdot 10^9 N

6 0
2 years ago
the distance between the sun and earth is about 1.5X10^11 m. express this distance with an SI prefix and kilometers
Angelina_Jolie [31]
First, we write the SI prefixed. The SI unit for distance is meters.

Kilo = 10³
Mega = 10⁶
Giga = 10⁹
Terra = 10¹²

Because our value has ten to the power of 11, we will use the closest and lowest power prefix, which is giga. 

1.5 x 10¹¹ /  10⁹
= 1.5 x 10² Gm or 150 Gm

Writing in kilometers, we simply repeat the procedure except we divide by 10³ this time.

1.5 x 10¹¹ / 10³
= 1.5 x 10⁸ km
5 0
2 years ago
Identical satellites X and Y of mass m are in circular orbits around a planet of mass M. The radius of the planet is R. Satellit
GrogVix [38]

Answer:

1) C

2) E

Explanation:

3 0
2 years ago
A bag containing originally 60 kg of flour is lifted through a vertical distance of 9 m. While it is being lifted, flour is leak
Art [367]

Answer:

The total work done is 5997.6 J

Solution:

As per the question:

Mass of the bag, m = 60 kg

Vertical distance, h = 9 m

Mass lost, m' = 12 kg

To calculate the amount of work done:

Lost mass is proportional to the square root of the distance covered while lifting:

m' ∝ \sqrt{h}

m' = K\sqrt{9}

where

K = proportionality constant

12 = 3K

K = 4

Mass of the floor containing bag at a height h:

m(h) = 60 - k\sqrt{h}

Work done is given by:

W = \int_{0}^{h}m(h)gdh

W = \int_{0}^{9}(60 - k\sqrt{h})gdh

W = g([60h]_{0}^{9} + 4\times \frac{2}{3}[h^{\frac{3}{2}}]_{0}^{9})

W = 9.8\times ([60\times 9 - 0] + \frac{8}{3}[9^{\frac{3}{2}} - 0^{\frac{3}{2}}])

W = 9.8\times (540 + \frac{8}{3}\times 27) = 5997.6\ J = 5.9976\ kJ

3 0
2 years ago
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