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Katarina [22]
1 year ago
5

In 1800, Herschel wondered if the different colors of the rainbow were equal in brightness and heat. He used a prism to separate

sunlight into it's different colors and thermometers to measure how much "heat energy" was included with each color. He also measured how much "brightness" was associated with each color. He noticed a "brightness" peak at the middle of the spectrum. Red and violet had the least amount of brightness with a "peak" at green and yellow. But for "heat energy", violet had the least and the amount of heat climbed more and more and showed no sign of a "peak" .
His observations supported the idea that neither Brightness nor heat were evenly distributed between the different colors. Some colors had more brightness (green and yellow) and a different color had the most heat (red).

But this lead to a new question. Did the "heat" exist even where there was no visible light and did it peak at wavelengths less than red. He did another set of experiments and found this to be the case. He again used a prism to separate sunlight into the colors of the rainbow. These colors were cast on a sheet of paper and a thermometer could be moved from one color to the next to measure the amount of heat. But this time, he moved the thermometers beyond the red light and made measurements on the paper where there was no visible light. He found the maximum amount of heat at wavelengths longer visible red light.


When Herschel selected where to place his thermometer and then measure the temperature, which variable was the Independent variable.

Question options:

A. The time of day


B. The month of the year


C. the temperature rise


D. the placement of the thermometer
Physics
1 answer:
Papessa [141]1 year ago
5 0

Answer:

D.

Explanation:

im guessing.

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Sunny_sXe [5.5K]

Answer:

In this case, the index of seawater replacement is 1.33, the index of refraction of air is 1, which is why the angle of replacement is less than the incident angle, so the fish seems to be closer

In the opposite case, when the fish looked at the face of the man, the angle of greater reason why it seems to be further away

Explanation:

This exercise can be analyzed with the law of refraction that establishes that a ray of light when passing from one medium to another with a different index makes it deviate from its path,

      n₁ sin θ₁ = n₂ sin θ₂

where n₁ and n₂ are the refractive indices of the incident and refracted means and the angles are also for these two means.

In this case, the index of seawater replacement is 1.33, the index of refraction of air is 1, which is why the angle of replacement is less than the incident angle, so the fish seems to be closer

1 sin θ₁ = 1.33 sin θ₂

        θ₂ = sin⁻¹ ( 1/1.33 sin θ₁)

In the opposite case, when the fish looked at the face of the man, the angle of greater reason why it seems to be further away

4 0
2 years ago
"The predictions of Einstein’s Theory of General Relativity were tested on a double pulsar system in January of 2004. His equati
Rasek [7]

Answer:

99.95%

Explanation:

A double pulsar system named PSR J0737-3039A/B  in Puppis constellation was discovered in the year 2003. Pulsars are second most densest object in the universe after black holes and they emit radio waves at regular intervals. This pair presented a great and natural setup to test the Theory of General Relativity presented by Einstein in 1915. In this theory Einstein had presented a set of equations on how the space-time fabric will be curved because of the very dense objects such as Neutron stars. It also predicted how the gravitational waves are created because of stars orbiting each other.

A team of astrophysicists led by Michael Kramer, conducted a study on how these gravitational waves will impact the time in which the radio waves emitted by pulsars will reach Earth. The result of the study proved the theory of General Relativity to be accurate up to 99.95%.

8 0
2 years ago
A rigid vessel of 0.06 m3 volume contains an ideal gas , CV =2.5R, at 500K and 1 bar.a). if 15000J heat is transferred to the ga
andreev551 [17]

Answer:

Given that

V= 0.06 m³

Cv= 2.5 R= 5/2 R

T₁=500 K

P₁=1 bar

Heat addition = 15000 J

We know that heat addition at constant volume process ( rigid vessel ) given as

Q = n Cv ΔT

We know that

P V = n R T

n=PV/RT

n= (100 x 0.06)(500 x 8.314)

n=1.443 mol

So

Q = n Cv ΔT

15000 = 1.433 x 2.5 x 8.314 ( T₂-500)

T₂=1000.12 K

We know that at constant volume process

P₂/P₁=T₂/T₁

P₂/1 = 1000.21/500

P₂= 2 bar

Entropy change given as

\Delta S=nC_P\ln \dfrac{T_2}{T_1}-nR\ln \dfrac{P_2}{P_1}

Cp-Cv= R

Cp=7/2 R

Now by putting the values

\Delta S=nC_P\ln \dfrac{T_2}{T_1}-nR\ln \dfrac{P_2}{P_1}

\Delta S=1.443\times 3.5\times 8.314\ln \dfrac{1000.21}{500}-1.443\times 8.314\ln \dfrac{2}{1}

a)ΔS= 20.79 J/K

b)

If the process is adiabatic it means that heat transfer is zero.

So

ΔS= 20.79 J/K

We know that

\Delta S_{univ}=\Delta S_{syatem}+\Delta S_{surr}

Process is adiabatic

\Delta S_{surr}=0

\Delta S_{univ}=\Delta S_{syatem}+\Delta S_{surr}

\Delta S_{univ}= 20.79 +0

\Delta S_{univ}= 20.79

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Look at the picture for the answer

7 0
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A 5.0-n projectile leaves the ground with a kinetic energy of 220 j. at the highest point in its trajectory, its kinetic energy
NikAS [45]
First, we get the difference between the kinetic energies such that,
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The difference in kinetic energy is the equivalent of the potential energy which is calculated through the equation,
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To calculate for the height, we derive the equation in a form,
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The product of the mass and acceleration due to gravity is the weight. 
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                   h = 20 m

<em>Hence, the answer is 20 m. </em>
3 0
2 years ago
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