Answer:
A) The new amplitude = 0.048 m
B) Period T = 0.6 seconds
Explanation: Please find the attached files for the solution
13200N
Explanation:
Given parameters:
Mass = 1100kg
Velocity = 24m/s
time = 2s
unknown:
Braking force = ?
Solution:
The braking force is the force needed to stop the car from moving.
Force = ma = 
m is the mass of the car
v is the velocity
t is the time taken
Force =
= 13200N
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Answer and Explanation: Kinetic energy is related to movement: it is the energy an object possesses during the movement. it is calculated as:

For the object thrown in the air:
![K=\frac{1}{2}.2.[v(t)]^{2}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7D.2.%5Bv%28t%29%5D%5E%7B2%7D)


Kinetic energy of the object as a function of time: 
Potential energy is the energy an object possesses due to its position in relation to other objects. It is calculated as:

For the object thrown in the air:



Potential energy as function of time: 
Total kinetic and potential energy, also known as mechanical energy is
TME =
+ (
)
TME = 1752
The expression shows that total energy of an object thrown in the air is constant and independent of time.
Answer:
0.6A
Explanation:
Area of loop =200cm2 =200 x10 ∧-4m∧2 Change in Magnetic field (B)= 25mT -10mT =15mT time =5ms
From Faraday' s law of induction EMF(E)= change in magnetic field/time
E= 15mT/5ms
Note, that one weber per second is equivalent to one volt.
= 3V
from Ohm's law I =E/R
=3/5 =0.6A
Answer:
Explanation:
It is required that the weight of Joe must prevent Simon from being pulled down . That means he is not slipping down but tends to be towed down . So in equilibrium , force of friction will act in upward direction on Simon.
Let in equilibrium , tension in rope be T
For balancing Joe
T = M g
For balancing Simon
friction + T = mgsinθ
μmgcosθ+T = mgsinθ
μmgcosθ+Mg = mgsinθ
M = (msinθ - μmcosθ)
M = m(sinθ - μcosθ)