Answer:
The final angular speed of the skater is 12 radians per second.
Explanation:
Let consider the skater as a rotating system, given the absence of external forces, the Principle of Angular Momentum Conservation is applied:
Where:
, 
- Initial and final moment of inertia, measured in 
.
, 
- Angular speed, measured in radians per second.
The final angular speed is cleared afterwards:
Given that 
and 
, the final angular speed is:
The final angular speed of the skater is 12 radians per second.
Answer:
1.024 × 10⁸ m
Explanation:
The velocity v₀ of the orbit 8RE is v₀ = 8REω where ω = angular speed.
So, ω = v₀/8RE
For the orbit with radius R for it to maintain a circular orbit and velocity 2v₀, we have
2v₀ = Rω
substituting ω = v₀/8RE into the equation, we have
2v₀ = v₀R/8RE
dividing both sides by v₀, we have
2v₀/v₀ = R/8RE
2 = R/8RE
So, R = 2 × 8RE
R = 16RE
substituting RE = 6.4 × 10⁶ m
R = 16RE
= 16 × 6.4 × 10⁶ m
= 102.4 × 10⁶ m
= 1.024 × 10⁸ m
Answer:
Explanation:
From the data it appears that A is the middle point between two charges.
First of all we shall calculate the field at point A .
Field due to charge -Q ( 6e⁻ ) at A
= 9 x 10⁹ x 6 x 1.6 x 10⁻¹⁹ / (2.5)² x 10⁻⁴
= 13.82 x 10⁻⁶ N/C
Its direction will be towards Q⁻
Same field will be produced by Q⁺ charge . The direction will be away
from Q⁺ towards Q⁻ .
We shall add the field to get the resultant field .
= 2 x 13.82 x 10⁻⁶
= 27.64 x 10⁻⁶ N/C
Force on electron put at A
= charge x field
= 1.6 x 10⁻¹⁹ x 27.64 x 10⁻⁶
= 44.22 x 10⁻²⁵ N
To find the number of electrons transferred, we should divide the total charge acquired by the rod
by the charge of a single electron (
), and we find:
Answer:
7.85 m/s^2
Explanation:
linear or tangential acceleration= dv/dt
⇒
=0.83 m/s^2
radial acceleration is given by = 
⇒
= 7.81 m/s^2
total acceleration
putting values we get
= 7.85 m/s^2
