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Mariana [72]
1 year ago
14

What is the wavelength of light waves if their frequency is 5.0x1014 Hz and the speed of light 3 x

Physics
1 answer:
Marat540 [252]1 year ago
5 0

Answer:

D. 0.60 um

Explanation:

Given the following data;

Frequency = 5.0x10^14 Hz

Speed = 3 x 10^8 m/s

To find the wavelength;

Wavelength = speed/frequency

Substituting into the equation, we have

Wavelength = 3 x 10^8/5.0x10^14

Wavelength = 6 × 10^7m

But 1 meter (m) = 1000000 micrometer (um)

6 × 10^7 meter = 0.6 micrometer.

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Write the equivalent formulas for velocity, acceleration, and force using the relationships covered for UCM, Newton’s Laws, and
yKpoI14uk [10]

Answer:

The newton’s second law is F=ma

The Gravitational force is F=\dfrac{Gm_{1}m_{2}}{r^2}

Explanation:

Given that,

The equivalent formulas for velocity, acceleration, and force using the relationships covered for UCM, Newton’s Laws, and Gravitation.

We know that,

Velocity :

The velocity is equal to the rate of position of the object.

v=\dfrac{dx}{dt}....(I)

Acceleration :

The acceleration is equal to the rate of velocity of the object.

a=\dfrac{dv}{dt}....(II)

Newton’s second Laws

The force is equal to the change in momentum.

In mathematically,

F=\dfrac{d(p)}{dt}

Put the value of p

F=\dfrac{d(mv)}{dt}

F=m\dfrac{dv}{dt}

Put the value from equation (II)

F=ma

This is newton’s second laws.

Gravitational force :

The force is equal to the product of mass of objects and divided by square of distance.

In mathematically,

F=\dfrac{Gm_{1}m_{2}}{r^2}

Where, m₁₂ = mass of first object

m= mass of second object

r = distance between both objects

Hence, The newton’s second law is F=ma

The Gravitational force is F=\dfrac{Gm_{1}m_{2}}{r^2}

3 0
2 years ago
A man stands on his balcony, 130 feet above the ground. He looks at the ground, with his sight line forming an angle of 70° with
jenyasd209 [6]

Answer:

d =  380 feet

Explanation:

Height of man = perpendicular= 130 feet

Angle of depression = ∅ = 70 °

distance to bus stop from man = hypotenuse = d = 130 sec∅

As sec ∅ = 1 / cos∅

so d = 130 sec∅    or d = 130 / cos∅

d = 130 / cos(70°)

d =  380 feet

8 0
2 years ago
The human ear canal is, on average, 2.5cm long and aids in hearing by acting like a resonant cavity that is closed on one end an
Troyanec [42]

Answer:

3400 Hz

Explanation:

We know that

1 cm = 0.01 m

L = Length of the human ear canal = 2.5 cm = 0.025 m

V = Speed of sound = 340 ms⁻¹

f = First resonant frequency

The human ear canal behaves as a closed pipe and for a closed pipe, nth resonant frequency is given as

f = \frac{(2n - 1)V}{4L}

for first resonant frequency, we have n = 1

Inserting the values

f = \frac{(2(1) - 1) 340}{4(0.025)}

f = \frac{340}{4(0.025)}

f = 3400 Hz

4 0
2 years ago
An object has a position given by r = [2.0 m + (2.00 m/s)t] i + [3.0 m − (1.00 m/s^2)t^2] j, where quantities are in SI units. W
lidiya [134]

Answer: 1 m/s

Explanation:

We have an object whose position r is given by a vector, where the components X and Y are identified by the unit vectors i and j (where each unit vector is defined to have a magnitude of exactly one):

r=[2 m + (2 m/s) t] i + [3 m - (1 m/s^{2})t^{2}] j

On the other hand, velocity is defined as the variation of the position in time:

V=\frac{dr}{dt}

This means we have to derive r:

\frac{dr}{dt}=\frac{d}{dt}[2 m + (2 m/s) t] i + \frac{d}{dt}[3 m - (1 m/s^{2})t^{2}] j

\frac{dr}{dt}=(2 m/s) i - (\frac{1}{2} m/s^{2} t) j This is the velocity vector

And when t=2s the velocity vector is:

\frac{dr}{dt}=(2 m/s) i - (\frac{1}{2} m/s^{2} (2 s)) j

\frac{dr}{dt}=2 m/s i - 1m/s j This is the velocity vector at 2 seconds

However, the solution is not complete yet, we have to find the module of this velocity vector, which is the speed S:

S=\sqrt {-1 m/s j + 2 m/s i}

S=\sqrt {1 m/s}

Finally:

S=1 m/s This is the speed of the object at 2 seconds

6 0
1 year ago
The inductor in a radio receiver carries a current of amplitude 200 mA when a voltage of amplitude 2.40 V is across it at a freq
White raven [17]

Answer:92

Explanation:

3 0
2 years ago
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