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devlian [24]
2 years ago
4

In a lab, a scientist calculate he should produce 12.3 grams of product in his experiment. When he is finished collecting his pr

oduct it weighs 11.0 grams. What is his percent yield?

Chemistry
1 answer:
Anestetic [448]2 years ago
8 0

Answer:

Option D.

Explanation:

Percentage yield = Actual yield / Theoretical yield * 100%

Actual yield = 11.0 grams

Theoretical yield = 12.3 grams

Percentage yield = 11.0 / 12.3  *  100

Percentage yield = 89.43%

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One container of turns costs 4 dollars. Each container has eighty 1g tablets. Assume each turns is 40% caco₃. Using only turns,
stealth61 [152]

<u>Answer:</u> The cost is coming out to be $ 1.25

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of HCl solution = 0.4 M

Volume of solution = 0.5 L

Putting values in equation 1, we get:

0.4M=\frac{\text{Moles of HCl}}{0.5L}\\\\\text{Moles of HCl}=(0.4mol/L\times 0.5L}=0.2mol

The chemical equation for the reaction of HCl and calcium carbonate follows:

CaCO_3+2HCl\rightarrow CaCl_2+H_2O+CO_2

By Stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of calcium carbonate

So, 0.2 moles of HCl will react with = \frac{1}{2}\times 0.2=0.1mol of calcium carbonate

To calculate the mass of calcium carbonate for given moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of calcium carbonate = 100 g/mol

Moles of calcium carbonate = 0.1 moles

Putting values in equation 1, we get:

0.1mol=\frac{\text{Mass of calcium carbonate}}{100g/mol}\\\\\text{Mass of calcium carbonate}=(0.1mol\times 100g/mol)=10g

  • Calculating the mass of calcium carbonate in 1 container:

We are given:

One container contains eighty 1 g of tablets, this means that in total 80 g of tablets are there.

Every container has 40 % calcium carbonate.

Mass of calcium carbonate in 1 container = 40 % of 80 g = \frac{40}{100}\times 80=32g

  • Calculating the containers for amount of calcium carbonate that neutralized HCl by using unitary method:

32 grams of calcium carbonate is present in 1 container

So, 10 g of calcium carbonate will be present in = \frac{1}{32}\times 10=0.3125 container

  • Calculating the cost of turns:

1 container of turns costs $4

So, 0.3125 containers of turns will cost = \frac{\$ 4}{1}\times 0.3125=\$ 1.25

Hence, the cost is coming out to be $ 1.25

4 0
2 years ago
A tank of oxygen has a volume of 40.0L and is held at a pressure of 159atm at 25∘C. What volume of O2 gas (in liters) would ther
Advocard [28]

Answer:

V2 = 6616 L

Explanation:

From the question;

Initial volume = 40L

Initial Pressure, P1 = 159atm

Initial Temperature T1 = 25 + 273 = 298K (Upon converting to Kelvin unit)

Final Volume, V2 = ?

Final Pressure, P2 = 1 atm

Final Temperature T2 = 37 + 273= 310K (Upon converting to Kelvin unit)

These quantities are related by the equation;

P1V1 / T1  = P2V2 / T2

V2 = T2 * P1 * V1 / T1 * P2

V2 = 310 * 159 * 40  /   (298 * 1)

V2 = 6616 L

6 0
1 year ago
What evidence do you have that atoms of certain elements produce a flame of a specific color?
AVprozaik [17]
Light acts as a wave so when you burn a certain element it generates a specific wavelength which represents a specific color light. ^-^
7 0
2 years ago
Unit Conversion Help Thank you
AlekseyPX

Answer : 1721.72 g/qt are in 18.2 g/cL

Explanation :

As we are given: 18.2 g/cL

Now we have to convert 18.2 g/cL to g/qt.

Conversions used are:

(1) 1 L = 100 cL

(2) 1 L = 1000 mL

(3) 1 qt = 946 qt

The conversion expression will be:

\frac{18.2g}{1cL}\times \frac{100cL}{1L}\times \frac{1L}{1000mL}\times \frac{946mL}{1qt}

=1721.72\text{ g/qt}

Therefore, 1721.72 g/qt are in 18.2 g/cL

5 0
2 years ago
Silver (ag) has a molar mass of 107.8682 g, nitrogen has a molar mass of 14.0067 g, and oxygen has a molar mass of 15.9994 g. wh
ASHA 777 [7]
AgNO3=
(ag + n + o3) =  \\  (107.8682) + (14.0067) + (15.9994 \times 3) \\  = 169.8731g \: per \: mole
3 0
2 years ago
Read 2 more answers
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