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Bumek [7]
2 years ago
15

To make a solution for an experiment, Gunther needs to add 40 g of a solute to 100 g of water. When making the solution at room

temperature, he could only add 34 grams before the solute settled out.
What could he do to dissolve the remaining 6 grams of the solute?

Put the solution in an ice bath, dissolve the solute, and let the solution return to room temperature.
Heat the solution, dissolve the solute, and let the solution cool verifying nothing settled out.
Add more water, boil the solution, and dissolve the solute until the some of the water evaporates.
Keep the solution at room temperature, add more water, and dissolve the excess solute.
Chemistry
1 answer:
777dan777 [17]2 years ago
5 0

Answer:

B. Heat the solution, dissolve the solute, and let the solution cool verifying nothing settled out.

Explanation:

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Be sure to answer all parts. Consider the following balanced redox reaction (do not include state of matter in your answers): 2C
timurjin [86]

Answer:

The specie which is oxidized is:- CrO_2^-

The specie which is reduced is:- ClO^-

Explanation:

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^{n+}+ne^-\rightarrow X

For the given chemical reaction:

2CrO_2^- + 6ClO^- + 2H_2O\rightarrow 2CrO_4^{2-} + 3Cl_2 + 4OH^-

The half cell reactions for the above reaction follows:

Oxidation half reaction:  CrO_2^- + 2H_2O + 4OH^-\rightarrow CrO_4^{2-} + 4H_2O + 3e^-

Reduction half reaction:  2ClO^- + 4H_2O + 2e^-\rightarrow Cl_2 + 2H_2O + 4OH^-

Thus, the specie which is oxidized is:- CrO_2^-

The specie which is reduced is:- ClO^-

8 0
3 years ago
When a stable diatomic molecule spontaneously forms from its atoms, what are the signs of Delta H, Delta S, and Delta G? A. + +
Neko [114]
H will definitely be positive because a bond is always more stable than no bond surely if it is a sigma bond.
For G you can't really know because you don't know how much energy is provided by the bond and if it outways the loss in disorder.


The reaction will become more spontaneous with a lower temperature because H tells you the reaction is exotherm
3 0
2 years ago
In a car piston shown above, the pressure of the compressed gas (red) is 5.00 atm. If the area of the piston is 0.0760 m^2. What
Shkiper50 [21]

Answer:

38503.5N

Explanation:

Data obtained from the question include:

P (pressure) = 5.00 atm

Now, we need to convert 5atm to a number in N/m2 in order to obtain the desired result of force in Newton (N). This is illustrated below:

1 atm = 101325N/m2

5 atm = 5 x 101325 = 506625N/m^2

A (area of piston) = 0.0760 m^2

Pressure is force per unit area. Mathematically it is written as

P = F/A

F = P x A

F = 506625 x 0.0760

F = 38503.5N

Therefore, the force exerted on the piston is 38503.5N

6 0
2 years ago
Click the "draw structure" button to launch the drawing utility. Propane (CH3CH2CH3) has both 1° and 2° hydrogens. Draw the carb
OlgaM077 [116]

Answer:

a) find attached image 1

b) find attached image 2

Explanation :

The more stable radical is formed by a reaction with smaller bond dissociation energy.

since the bond dissociation for cleavage of the bond to form primary free radical is higher, more energy must be added to form it. This makes primary free radical higher in energy and therefore less stable than secondary free radical.

6 0
2 years ago
4p + 5O2 -> P4O10 ; the percent yield of PO4O10 when 6.20 g of phosphorus burns into excess oxygen is 67.0%. What is the yiel
denis23 [38]

Answer:    36.9 g

Explanation:

P4 + 5O2 = P4O10  Balanced equation

moles P4 present = 23.9 g x 1 mole/123.88 g = 0.193 moles

moles O2 present = 20.8 g x 1 mol/32 g = 0.65 moles O2

From balanced equation, mole ratio O2 : P4 is 5:1.  Is 0.65 moles O2 5x 0.193 moles?  NO.  You don't have enough O2.

O2 is limiting in this reaction.

 

theoretical moles of P4O10 = 0.65 moles O2 x 1 mole P4O10/5 moles O2 = 0.13 moles P4O10

mass of P4O10 produced = 0.13 moles x 283.9 g = 36.9 g

3 0
1 year ago
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