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Bumek [7]
2 years ago
15

To make a solution for an experiment, Gunther needs to add 40 g of a solute to 100 g of water. When making the solution at room

temperature, he could only add 34 grams before the solute settled out.
What could he do to dissolve the remaining 6 grams of the solute?

Put the solution in an ice bath, dissolve the solute, and let the solution return to room temperature.
Heat the solution, dissolve the solute, and let the solution cool verifying nothing settled out.
Add more water, boil the solution, and dissolve the solute until the some of the water evaporates.
Keep the solution at room temperature, add more water, and dissolve the excess solute.
Chemistry
1 answer:
777dan777 [17]2 years ago
5 0

Answer:

B. Heat the solution, dissolve the solute, and let the solution cool verifying nothing settled out.

Explanation:

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Ammonia has a Kb of 1.8 × 10−5. Find [H3O+], [OH−], pH, and pOH for a 0.310 M ammonia solution.
lawyer [7]

Answer:

[H₃O⁺] = 4.3 × 10⁻¹² mol·L⁻¹; [OH⁻] = 2.4 × 10⁻³ mol·L⁻¹;

pH = 11.4; pOH = 2.6

Explanation:

The chemical equation is

\rm NH$_{3}$ + \text{H}$_{2}$O \, \rightleftharpoons \,$ NH$_{4}^{+}$ + \,\text{OH}$^{-}$

For simplicity, let's re-write this as

\rm B + H$_{2}$O \, \rightleftharpoons\,$ BH$^{+}$ + OH$^{-}$

1. Calculate [OH]⁻

(a) Set up an ICE table.  

   B + H₂O ⇌ BH⁺ + OH⁻

0.310               0        0

   -x                  +x      +x

0.310-x               x        x

K_{\text{b}} = \dfrac{\text{[BH}^{+}]\text{[OH}^{-}]}{\text{[B]}} = 1.8 \times 10^{-5}\\\\\dfrac{x^{2}}{0.100 - x} = 1.8 \times 10^{-5}

Check for negligibility:

\dfrac{0.310}{1.8 \times 10^{-5}} = 17 000 > 400\\\\x \ll 0.310

(b) Solve for [OH⁻]

\dfrac{x^{2}}{0.310} = 1.8 \times 10^{-5}\\\\x^{2} = 0.310 \times 1.8 \times 10^{-5}\\x^{2} = 5.58 \times 10^{-6}\\x = \sqrt{5.58 \times 10^{-6}}\\x = \text{[OH]}^{-} = \mathbf{2.4 \times 10^{-3}} \textbf{ mol/L}

2. Calculate the pOH

\text{pOH} = -\log \text{[OH}^{-}] = -\log(2.4 \times 10^{-3}) = \mathbf{2.6}

3. Calculate the pH

\text{pH} = 14.00 - \text{pOH} = 14.00 - 2.6 = \mathbf{11.4}

4 Calculate [H₃O⁺]

\text{H$_{3}$O$^{+}$} = 10^{-\text{pH}} = 10^{-11.4} = \mathbf{4.2 \times 10^{-12}} \textbf{ mol/L}

5 0
1 year ago
Which statement about gases is true? A. They are made up of particles that always move very slowly. B. They are made up of parti
rosijanka [135]

Answer: D. They are made up of hard spheres that are in random motion.

Explanation:

A gas is a <u>state of aggregation of matter</u> in which, under certain conditions of temperature and pressure, <u>its molecules interact weakly with each other, without forming molecular bonds</u>, adopting the shape and volume of the container that contains them and tending to separate everything possible because of its <u>high concentration of kinetic energy</u>.

The molecules of a gas are practically <u>free</u> and have the ability to be distributed throughout the space in which they are contained because <u>the gravitational forces and attraction between them are practically negligible</u> compared to the speed at which they move. .

Therefore, gas molecules do not travel specific trajectories or vibrate in a stationary position, instead <u>they move quickly and randomly through the entire space of the container that contains them.</u>

7 0
1 year ago
Read 2 more answers
Calculate the amount of work done against an atmospheric pressure of 1.00 atm when 500.0 g of zinc dissolves in excess acid at 3
ZanzabumX [31]

Answer:

19,26 kJ

Explanation:

The work done when a gas expand with a constant atmospheric pressure is:

W = PΔV

Where P is pressure and ΔV is the change in volume of gas.

Assuming the initial volume is 0, the reaction of 500g of Zn with H⁺ (Zn(s) + 2H⁺(aq) → Zn²⁺(aq) + H₂(g)) produce:

500,0g Zn(s)×\frac{1molZn}{65,38g}×\frac{1molH_{2}(g)}{1molZn} = 7,648 moles of H₂

At 1,00atm and 303,15K (30°C), the volume of these moles of gas is:

V = nRT/P

V = 7,648mol×0,082atmL/molK×303,15K / 1,00atm

V = 190,1L

That means that ΔV is:

190,1L - 0L = <em>190,1L</em>

And the work done is:

W = 1atm×190,1L = 190,1atmL.

In joules:

190,1 atmL×\frac{101,325}{1atmL} = <em>19,26 kJ</em>

I hope it helps!

5 0
2 years ago
The radius of a potassium atom is 231 pm. How many potassium atoms would have to be laid side by side to span a distance of 4.77
Softa [21]
To determine the number of potassium laid side by side by a given distance, we simply divide the total distance to the diameter of each atom. The diameter is twice the radius of the atom. We calculate as follows:

number of atoms = 4770 / 231x10^-12 = 2.06x10^13 atoms
3 0
2 years ago
Read 2 more answers
Draw the structure of (z)-3-methylhept-3-ene. be sure the stereochemistry is drawn clearly.
aivan3 [116]
In  alkene  if two  substituent and  hydrogen  are  attached  in  the isomer  may  be cis  or trans. When  two  or  more substitution  are attached  to  an alkene  the  isomer  may  be  Z or E.All cis  are  Z isomer. The  structure  of  (Z)-3-methy-3-heptene  is  as  the  following  attachment

6 0
2 years ago
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