Answer:
<h2>It must be shown that both j(k(x)) and k(j(x)) equal x</h2>
Step-by-step explanation:
Given the function j(x) = 11.6
and k(x) =
, to show that both equality functions are true, all we need to show is that both j(k(x)) and k(j(x)) equal x,
For j(k(x));
j(k(x)) = j[(ln x/11.6)]
j[(ln (x/11.6)] = 11.6e^{ln (x/11.6)}
j[(ln x/11.6)] = 11.6(x/11.6) (exponential function will cancel out the natural logarithm)
j[(ln x/11.6)] = 11.6 * x/11.6
j[(ln x/11.6)] = x
Hence j[k(x)] = x
Similarly for k[j(x)];
k[j(x)] = k[11.6e^x]
k[11.6e^x] = ln (11.6e^x/11.6)
k[11.6e^x] = ln(e^x)
exponential function will cancel out the natural logarithm leaving x
k[11.6e^x] = x
Hence k[j(x)] = x
From the calculations above, it can be seen that j[k(x)] = k[j(x)] = x, this shows that the functions j(x) = 11.6
and k(x) =
are inverse functions.
I got the answer Antonio had a head start of 3 meters.
Answer:
1900 meters
Step-by-step explanation:
He ran for 850 meters
Walked for 2.75 kilometers, and that's 2.75 * 1000 meters, which is 2750 meters
The total he walked more than he ran is 2750 - 850 = 1900 meters
The mean is just the arithmetic average...
Sample A=8.1
Sample B=8.11
Both Samples=8.105
So Ryan would be closer to being correct given either of or both samples.
Answer:
i don't see the graph
Step-by-step explanation: