Question

1. How did velocity (v) and velocity squared (v2) relate to the height from which the ball was released? Use the relationships from your graphs in your explanation. Which one, if any, was linearly related to the height?

Answer 1

Once the ball is released it starts to twirl and spin catching the flow of the air causing it to go faster or slower

Answer 2

Answer:

speed(v) will depends of square root of height so it would be a parabolic graph

square of the speed($v^2$) is directly proportional to height so it would be a straight line graph.

Explanation:

As we know by formula of kinematic that

$v^2 - u^2 = 2 a y$

here a = acceleration due to gravity(g)

also if object start its motion from rest

$u = 0$

so we have

$v^2 = 2gy$

also we can write it as

$v = \sqrt{2gy}$

so here since square of the speed is proportional to the height so the graph between them is always a straight line.

While if we see another relation then speed is proportional to the square root of height so it would be a parabolic graph