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2 years ago

5

A bicyclist of mass 112 kg rides in a circle at a speed of 8.9 m/s. If the radius of the circle is 15.5 m, what is the centripet

al force on the bicyclist?

2 answers:

Goryan [66]2 years ago

5 0

Hello!

A bicyclist of mass 112 kg rides in a circle at a speed of 8.9 m/s. If the radius of the circle is 15.5 m, what is the centripetal force on the bicyclist ?

We have the following data:

Centripetal Force = ? (Newton)

m (mass) = 112 Kg

s (speed) = 8.9 m/s

R (radius) = 15.5 m

Formula:

$\boxed{F_{centripetal\:force} = \dfrac{m*s^2}{R}}$

Solving:

$F_{centripetal\:force} = \dfrac{m*s^2}{R}$

$F_{centripetal\:force} = \dfrac{112*8.9^2}{15.5}$

$F_{centripetal\:force} = \dfrac{112*79.21}{15.5}$

$F_{centripetal\:force} = \dfrac{8871.52}{15.5}$

$F_{centripetal\:force} = 572.356129...$

$\boxed{\boxed{F_{centripetal\:force} \approx 572.36\:N}}\end{array}}\qquad\checkmark$

Answer:

The centripetal force on the bicyclist is approximately 572.36 N

____________________________________

I Hope this helps, greetings ... Dexteright02! =)

kogti [31]2 years ago

4 0

The centripetal force, Fc, is calculated through the equation,
Fc = mv²/r
where m is the mass,v is the velocity, and r is the radius.
Substituting the known values,
Fc = (112 kg)(8.9 m/s)² / (15.5 m)
= 572.36 N
Therefore, the centripetal force of the bicyclist is approximately 572.36 N.

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