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polet [3.4K]
2 years ago
14

Which is found farthest from the center of an atom?

Physics
1 answer:
xxTIMURxx [149]2 years ago
5 0
Electron

Hope this helps
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A sound technician is testing the sound acoustics in a theatre for an upcoming music concert. As he moves towards the speakers,
Harlamova29_29 [7]

Answer: Increase in wave frequency

Explanation:

When we talk about acoustics we are dealing with sound waves, and one of their main components along with the velocity and wavelength is the <u>frequency.</u>

In this sense, the frequency of any wave refers to how fast (or slow) a wave oscillates. For example, in the especific case of sound waves when the oscillation is faster, the frequency is higher and the pitch gets higher as well.

6 0
2 years ago
Read 2 more answers
A heat engine (Power Cycle) with a thermal efficiency of 35 percent efficiency produces 750 kJ of work. Heat transfer to the eng
frosja888 [35]

Answer:

a) The schematic illustrating is attached

b) The heat transfer to the heat engine is 2142.86 kJ, the heat transfer from the heat engine is 1392.86 kJ

c) The heat transfer to the heat engine is 1648.35 kJ, the heat transfer from the heat engine is 898.35 kJ

Explanation:

b) The heat transfer to the engine and the heat transfer from the engine to the air is:

Q_{1} =\frac{W}{n}

Where

W = 750 kJ

n = 35% = 0.25

Replacing:

Q_{1} =\frac{750}{0.35} =2142.86kJ

Q_{2} =Q_{1} -W=2142.86-750=1392.86kJ

c) The efficiency of Carnot engine is:

n=1-\frac{300K}{550K} =0.455

The heat transfer to the heat engine is:

Q_{1c} =\frac{750}{0.455} =1648.35kJ

The heat transfer from the heat engine is:

Q_{2c} =1648.35-750=898.35kJ

4 0
2 years ago
A pulley 12 cm in diameter is free to rotate about a horizontal axle. A 220-g mass and a 470-g mass are tied to either end of a
Aleks [24]

Answer:0.147 N-m

Explanation:

Given

Diameter of Pulley d=12 cm

radius r=6 cm

mass of first object m_1=220 gm

mass of second object m_2=470 gm

Now both masses will exert a torque a on Pulley

Torque due to first Pulley T_1=m_1g\cdot r

T_1=0.22\times 9.8\times 0.06=0.129 N-m

Torque due to second mass on Pulley T_2=m_2g\cdot r

T_2=0.276 N-m

Total Torque by masses T_{net}=T_2-T_1

T_{net}=0.276-0.129=0.147 N-m

so we need to apply a torque of magnitude 0.147 N-m opposite to the direction of T_{net}  

3 0
2 years ago
A combined circuit has two resistors in series (27.5 ohms and 33.0 ohms) and another in parallel (22.0 ohms). If the power sourc
Dafna1 [17]
R 1,2 = 27.5 + 33.0 = 60.5 Ohms
1/ R 1,2,3 = 1/ 60.5 + 1 / 22 = 82.5 / 1331
R 1, 2, 3 = 1331 / 82.5 = 16.13 Ohms
I = U / R
I = 9 V / 16.13 Ohms = 0.557 A ≈ 0.56 A
Answer: C ) 0.56 Amps 
4 0
2 years ago
What is the total flux φ that now passes through the cylindrical surface? enter a positive number if the net flux leaves the cyl
trasher [3.6K]

Net flux through the cylindrical surface is given as

\phi = \frac{q}{epsilon_0}

here q = enclosed charge in the surface

so here in order to find the value of q

q = \lambda* L

so now we have

\phi = \frac{\lambda * L}{\epsilon_0}

so this is the total flux

now by Gauss's law we can find the electric field

\int E.dA = \phi

\int E.dA = \frac{\lambda * L}{\epsilon_0}

E* 2\pi rL = \frac{\lambda * L}{epsilon_0}

E = \frac{\lambda}{2\pi \epsilon_0 r}

<em>by above expression we can find the electric field at required position</em>

8 0
2 years ago
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