Which is found farthest from the center of an atom?

A sound technician is testing the sound acoustics in a theatre for an upcoming music concert. As he moves towards the speakers,

Harlamova29_29 [7]

Answer: Increase in wave frequency

Explanation:

When we talk about acoustics we are dealing with sound waves, and one of their main components along with the velocity and wavelength is the <u>frequency.</u>

In this sense, the frequency of any wave refers to how fast (or slow) a wave oscillates. For example, in the especific case of sound waves when the oscillation is faster, the frequency is higher and the pitch gets higher as well.

6 0

2 years ago

Read 2 more answers

A heat engine (Power Cycle) with a thermal efficiency of 35 percent efficiency produces 750 kJ of work. Heat transfer to the eng

frosja888 [35]

Answer:

a) The schematic illustrating is attached

b) The heat transfer to the heat engine is 2142.86 kJ, the heat transfer from the heat engine is 1392.86 kJ

c) The heat transfer to the heat engine is 1648.35 kJ, the heat transfer from the heat engine is 898.35 kJ

Explanation:

b) The heat transfer to the engine and the heat transfer from the engine to the air is:

$Q_{1} =\frac{W}{n}$

Where

W = 750 kJ

n = 35% = 0.25

Replacing:

$Q_{1} =\frac{750}{0.35} =2142.86kJ$

$Q_{2} =Q_{1} -W=2142.86-750=1392.86kJ$

c) The efficiency of Carnot engine is:

$n=1-\frac{300K}{550K} =0.455$

The heat transfer to the heat engine is:

$Q_{1c} =\frac{750}{0.455} =1648.35kJ$

The heat transfer from the heat engine is:

$Q_{2c} =1648.35-750=898.35kJ$

4 0

2 years ago

A pulley 12 cm in diameter is free to rotate about a horizontal axle. A 220-g mass and a 470-g mass are tied to either end of a

Aleks [24]

Answer:0.147 N-m

Explanation:

Given

Diameter of Pulley $d=12 cm$

radius $r=6 cm$

mass of first object $m_1=220 gm$

mass of second object $m_2=470 gm$

Now both masses will exert a torque a on Pulley

Torque due to first Pulley $T_1=m_1g\cdot r$

$T_1=0.22\times 9.8\times 0.06=0.129 N-m$

Torque due to second mass on Pulley $T_2=m_2g\cdot r$

$T_2=0.276 N-m$

Total Torque by masses $T_{net}=T_2-T_1$

$T_{net}=0.276-0.129=0.147 N-m$

so we need to apply a torque of magnitude 0.147 N-m opposite to the direction of $T_{net}$

3 0

2 years ago

A combined circuit has two resistors in series (27.5 ohms and 33.0 ohms) and another in parallel (22.0 ohms). If the power sourc

Dafna1 [17]

R 1,2 = 27.5 + 33.0 = 60.5 Ohms
1/ R 1,2,3 = 1/ 60.5 + 1 / 22 = 82.5 / 1331
R 1, 2, 3 = 1331 / 82.5 = 16.13 Ohms
I = U / R
I = 9 V / 16.13 Ohms = 0.557 A ≈ 0.56 A
Answer: C ) 0.56 Amps

4 0

2 years ago

What is the total flux φ that now passes through the cylindrical surface? enter a positive number if the net flux leaves the cyl

trasher [3.6K]

Net flux through the cylindrical surface is given as

$\phi = \frac{q}{epsilon_0}$