Which is found farthest from the center of an atom?

The number that is used to show the value of one currency compared to another is called the __________. A. trade rate B. currenc

Brrunno [24]

Answer:

c is the answer

Explanation:

8 0

2 years ago

What makes the subject of star formation so difficult and complex? Star formation is too expensive to study in detail. Stars liv

marta [7]

Answer:

Stars live to long to be observed from birth to death

Explanation:

The life expectancy of a star are millions of years compared to that of human thereby making it difficult to study the life path and activities of the stars till the point of extinction. This brought about scientist studying different star with different ages in order to answer their burning question on formation of stars which is called the figuring out process(stellar activity) and this makes it difficult and tedious.

5 0

2 years ago

Rod AB is held in place by the cord AC. Knowing that the tension in the cord is 1350 N and that c 5 360 mm, determine the moment

riadik2000 [5.3K]

Answer:

291.598 N-m

291.6 N-m

Explanation:

Let's first take a look at the free bodily diagrammatic representation.

The first diagram will aid us in answering question (a), so as the second diagram will facilitate effective understanding when solving for question (b).

Let's first determine our angle θ from the diagram

To find angle θ ; we have :

tan θ = $\frac{360+240}{450}$

tan θ = $\frac{600}{450}$

tan θ = 1.333

θ = tan⁻¹ (1.333)

θ = 53.13°

Now, to determine the moment about B of the force exerted by the cord at point A by resolving that force into horizontal and vertical components applied at point A.

We have:

$M__B}=(Fcos \theta *240)-(Fsin \theta *450)$

where Force(F) = Force in the cord AC = 1350 N and θ = 53.13° ; we have:

$M__B}=(1350&cos 53.13^0 *240)-(1350sin 53.13^0 *450)$

$M__B}= 194400.463-485999.348$

$M__B}=-291598.885 N-mm\\$

$M__B}=-291.598 N-m$

Since the negative sign illustrates just the clockwise movement ; then the moment about B of the force exerted by the cord at point A by resolving that force into horizontal and vertical components applied at point A = 291.598 N-m

b) From the second diagram, taking the moment at point B $(M__B})$ ,

we have:

$M__B}=-Fcos \theta *360 - Fsin \theta * 0$

$M__B}=-Fcos \theta *360 - 0$

$M__B}=-Fcos \theta *360$

where Force(F) = 1350 N and θ = 53.13° ; we have:

$M__B}= -1350*cos53.13^0*360$

$M__B}= -291600 N-mm$

$M__B}= -291.6 N-m$

Since the negative sign illustrates just the clockwise movement ; then the moment about B of the force exerted by the cord at point A by resolving that force into horizontal and vertical components applied at point C = 291.6 N-m

6 0

2 years ago

Keisha looks out the window from a tall building at her friend Monique standing on the ground, 8.3 m away from the side of the b

Salsk061 [2.6K]

Answer:

Explanation:

GIVEN DATA:

Distance between keisha and her friend 8.3 m

angle made by keisha toside building 30 degree

height of her friend monique is 1.5 m

from the figure

$\Delta ACB$

$tan 30 = \frac{8.3}{h}$

$h= \frac{8.3}{tan 30} = 14.376 m$

therefore

height of keisha is $= h + 1.5 m$

= 14.376 + 1.5

$= 15.876 \simeq 16 m$

therefore option c is correct

5 0

2 years ago

A rocket moves through outer space a 12,000 m/s. At this time, how much time would be required to travel the distance from Earth

nexus9112 [7]

12000 m/s = 12 km/s. Now to go 380000 km, it will take some time. How much time is given in the formula 12km/s. You go 12 kilometers every second. So you take $\frac{380000km}{12km/s}$ and that gives you 31,666.666 seconds.

6 0

2 years ago

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