Car A leaves town heading east with a constant speed of 20 miles/hr. An hour later Car B leaves town heading east as well, with
1 answer:
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Answer:
height of the water rise in tank is 10ft
Explanation:
Apply the bernoulli's equation between the reservoir surface (1) and siphon exit (2)
-------(1)
substitute
0ft/s for V₁, 20ft for (z₁ - z₂) and 32.2ft/s² for g in eqn (1)
Applying bernoulli's equation between tank surface (3) and orifice exit (4)
substitute
0ft/s for V₃, h for z₃, 0ft for z₄, 32,2ft/s² for g
At equillibrium Fow rate at point 2 is equal to flow rate at point 4
Q₂ = Q₄
A₂V₂ = A₃V₃
The diameter of the orifice and the siphon are equal , hence there area should be the same
substitute A₂ for A₃
for V₂
for V₄
A₂V₂ = A₃V₃
Therefore ,height of the water rise in tank is 10ft
Answer:
The ball reaches Barney head in
Explanation:
From the question we are told that
The rise velocity is
The height considered is
The horizontal velocity of the large object is
Generally from kinematic equation
Here s is the distance of the object from Barney head ,
u is the velocity of the object along the vertical axis which is equal but opposite to the velocity of the helicopter
So
So
=
Solving the above equation using quadratic formula
The value of t obtained is