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Greeley [361]
1 year ago
11

A stone weighing 1.5 kilograms is resting on a rock at a height of 20 meters above the ground. The stone rolls down 10 meters an

d comes to rest on a patch of moss. The gravitational potential energy of the stone on the moss is joules. (Use PE = m × g × h, where g = 9.8 N/kg.)
Physics
2 answers:
Andrews [41]1 year ago
6 0
The potential energy of the moss at its position is 147 Joules. 
34kurt1 year ago
4 0
Given that the equation for the potential energy of an object is: PE = mgh, where, m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above the ground, simply substitute the given values to obtain the potential energy. In this case, m = 1.5 kg, g = 9.8 N/kg, and h = 10 m. The height is set to 10 m since this is the height of the moss above the ground after it fell. Thus, the potential energy of the moss at its position is 147 Joules. 
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Several charges in the neighborhood of point P produce an electric potential of 6.0 kV (relative to zero at infinity) and an ele
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Answer:

0.018 J

Explanation:

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W = q \Delta V

where

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\Delta V = 6.0 kV = 6000 V is the potential difference between point P and infinity

Substituting into the equation, we find

W=(3.0\cdot 10^{-6}C)(6000 V)=0.018 J

4 0
2 years ago
Suppose you push a hockey puck of mass m across frictionless ice for a time 1.0 s, starting from rest, giving the puck speed v a
EleoNora [17]
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I think I've made a mistake somewhere below, but I think that the principle is right ...using one of the kinematic equations for m ...  s=ut + (1/2)at^2); s=d;u=0;a=F/m; t=1;  -> d=(1/2)(F/m)=F/2musing one of the kinematic equations for 2m ...  s=ut + (1/2)at^2); s=d;u=0;a=F/2m; t=1;  -> d=(1/2)(F/2m)=F/4m (half as far ????? WHAT ???)
3 0
1 year ago
Read 2 more answers
Hoosier Manufacturing operates a production shop that is designed to have the lowest unit production cost at an output rate of 1
abruzzese [7]

Answer:

90.77%

its capacity utilization rate for the month is 90.77%

Explanation:

The capacity utilisation rate can be expressed mathematically as;

Capacity utilisation rate = capacity used/Best operating level × 100%

Given;

Total Number of production time = 205hours

Production output/capacity used = 21400 units

Best operation rate = 115units/hour

Best operation output for the month of July( at best operation level )

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Capacity utilisation rate = 21400/23575 × 100%

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3 0
2 years ago
Which of the following best describes a capacitor?
galben [10]

Answer:

B

Explanation:

The capacitor is a component which has the ability to store energy in the form of an electrical charge  making a potential difference on those two metal plates

A capacitor consists of two or more parallel conductive (metal) plates. They are electrically seperated by an insulating material (ex: air, mica,ceramic etc.) which is called as Dielectric Layer

Due to this insulating layer, DC current can not flow through the capacitor.But it allows a voltage to be present across the plates in the form of an electrical charge.

4 0
1 year ago
Read 2 more answers
A sample of an ideal gas is in a tank of constant volume. The sample absorbs heat energy so that its temperature changes from 38
oksano4ka [1.4K]

Answer:

the ratio is \frac{V_2}{V_1}=\sqrt{2}

Explanation:

Given

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k_b=constant

For T = 387K

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For T = 774

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dividing eqn 1 and eqn 2

\frac{V_2}{V_1}=\sqrt{\frac{774}{387}}

\frac{V_2}{V_1}=\sqrt{2}

Thus,the ratio is \frac{V_2}{V_1}=\sqrt{2}

5 0
2 years ago
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