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12345 [234]
2 years ago
12

the atlantic torpedo is a large electric fish capable of generating a voltage of 220V between its tail and its head. This drives

a pulse of current of 15A lasting for a time of 2.0ms. The fish produces 200 pulses per second. What is the average power output of the fish? a.33W b.1.3KW c.3.3KW d.6.6KW
Physics
1 answer:
Elza [17]2 years ago
7 0
The average power output:
P = V * I * t
V = 220 V, I = 15 A;
t = 2 ms * 200 = 400 ms = 0.4 s
P = 220 V * 15 A * 0.4 s
P = 1320 W ≈ 1.3 kW
Answer:
b. 1.3 kW
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Point m is located a distance 2d from the midpoint between the two wires. find the magnitude of the magnetic field b1m created a
Tema [17]

Note: The diagram referred to in the question is attached here as a file.

Answer:

The magnitude of the magnetic field is B = \frac{0.071 \mu I}{d}

Explanation:

The magnetic field can be determined by the relationship:

B = \frac{\mu I}{2\pi R}...............(1)

Were I is the current flowing through the wires

The distance R from point 1 to m is calculated using the pythagora's theorem

R = \sqrt{d^{2} + (2d)^{2}  }

R = \sqrt{5d^{2} } \\R = d\sqrt{5}

Substituting R into equation (1)

B = \frac{\mu I}{2\pi d\sqrt{5} }

B = \frac{0.071 \mu I}{d}

3 0
2 years ago
The table shows information about four students who are running around a track. Which statement is supported by the information
Vikentia [17]

Answer:

<em>Correct option: Mohammed has less kinetic energy than Autumn.</em>

Explanation:

<u>Kinetic Energy</u>

Is the energy an object has due to its motion. If the object has a mass m and travels at a speed v, then the kinetic energy K is:

\displaystyle K=\frac{1}{2}mv^2

The information about four students includes their mass and velocity as follows:

Autumn has a mass of m1=50 kg and a velocity (magnitude) of v1=4 m/s, thus their kinetic energy is:

\displaystyle K_1=\frac{1}{2}50\cdot 4^2

K_1=400\ J

Mohammed has a mass of m2=57 kg and a velocity (magnitude) of v2=3 m/s, thus their kinetic energy is:

\displaystyle K_2=\frac{1}{2}57\cdot 3^2

K_2=256.5\ J

Lexy has a mass of m3=53 kg and a velocity (magnitude) of v3=2 m/s, thus their kinetic energy is:

\displaystyle K_3=\frac{1}{2}53\cdot 2^2

K_3=106\ J

Chiang has a mass of m4=64 kg and a velocity (magnitude) of v4=5 m/s, thus their kinetic energy is:

\displaystyle K_4=\frac{1}{2}64\cdot 5^2

K_4=800\ J

Sorted from lower kinetic energy to higher:

Lexy, Mohammed, Autumn, Chiang. Thus:

Autumn has more kinetic energy than Chiang. False

Mohammed has less kinetic energy than Autumn. True

Lexy has more kinetic energy than Mohammed. False

Chiang has less kinetic energy than Lexy. False

Correct option: Mohammed has less kinetic energy than Autumn.

3 0
2 years ago
Read 2 more answers
A neutron star has a mass of 2.0 × 1030 kg (about the mass of our sun) and a radius of 5.0 × 103 m (about the height of a good-s
laiz [17]

Answer:

30298514.82 m/s

Explanation:

M = Mass of star = 2×10³ kg

r = Radius of star = 5×10³ m

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

a=G\frac{M}{r^2}\\\Rightarrow a=6.67\times 10^{-11}\frac{2\times 10^{30}}{5\times 10^3}\\\Rightarrow a=2.7\times 10^{16}\ m/s^2

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 2.7\times 10^{16}\times 0.017+0^2}\\\Rightarrow v=30298514.82\ m/s

The object would be moving at a velocity of 30298514.82 m/s

5 0
2 years ago
Read 2 more answers
A responder can protect himself/herself from radiation by using shielding as a response action. What materials are best for prot
Irina-Kira [14]

Answer:

Few millimeter thick aluminium, water, wood, acrylic glass or plastic.

Explanation:

The materials that are best for protection against beta particles are few millimeter thickness of aluminium, but for the high energy beta-particles radiations the low atomic mass materials such as plastic, wood, water and acrylic glass can be used.

These materials can also be used in personal protective equipment which includes all the clothing that can be worn to prevent any injury or illness due to the exposure to radiation.

3 0
2 years ago
A circular coil of wire of 200 turns and diameter 2.0 cm carries a current of 4.0 A. It is placed in a magnetic field of 0.70 T
DerKrebs [107]

Answer:

0.087976 Nm

Explanation:

The magnetic torque (τ) on a current-carrying loop in a magnetic field is given by;

τ = NIAB sinθ     --------- (i)

Where;

N = number of turns of the loop

I = current in the loop

A = area of each of the turns

B = magnetic field

θ = angle the loop makes with the magnetic field

<em>From the question;</em>

N = 200

I = 4.0A

B = 0.70T

θ = 30°

A = π d² / 4        [d = diameter of the coil = 2.0cm = 0.02m]

A = π x 0.02² / 4 = 0.0003142m²         [taking π = 3.142]

<em>Substitute these values into equation (i) as follows;</em>

τ = 200 x 4.0 x 0.0003142 x 0.70 sin30°

τ = 200 x 4.0 x 0.0003142 x 0.70 x 0.5

τ = 200 x 4.0 x 0.0003142 x 0.70      

τ = 0.087976 Nm

Therefore, the torque on the coil is 0.087976 Nm

3 0
2 years ago
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