I attached the missing picture.
We can figure this one out using the law of conservation of energy.
At point A the car would have potential energy and kinetic energy.

Then, while the car is traveling down the track it loses some of its initial energy due to friction:

So, we know that the car is approaching the point B with the following amount of energy:

The law of conservation of energy tells us that this energy must the same as the energy at point B.
The energy at point B is the sum of car's kinetic and potential energy:

As said before this energy must be the same as the energy of a car approaching the loop:

Now we solve the equation for

:
Answer:
Explanation:
The rate at which heat will be radiated is given by the expression
E = e Aσ ( T⁴ - T₀⁴ )
E is heat radiated , e is emissivity , A is area of surface , σ is stephan's constant T is temperature of the object and T₀ is temperature of the surrounding .
For all the objects given , e , σ T and T₀ are same so E will solely dependent on area of the surface
surface area of cube= 6 r² ,
surface area of sphere = 4 π r²
= 12.56 r²
hemisphere = 2 π r²
= 6.28 r²
12.56 r² >6.28 r² > 6 r²
heat radiated by sphere > heat radiated by hemisphere > heat radiated by cube .
<span>Answers: (a) 2.0 m/s (b) 4 m/s
Method:
(a) By conservation of momentum, the velocity of the center of mass is unchanged, i.e., 2.0 m/s.
(b) The velocity of the center of mass = (m1v1+m2v2) / (m1+m2)
Since the second mass is initially at rest, vcom = m1v1 / (m1+m2)
Therefore, the initial v1 = vcom (m1+m2) / m1 = 2.0 m/s x 6 = 12 m/s
Since the second mass is initially at rest, v2f = v1i (2m1 /m1+m2 ) = 12 m/s (2/6) = 4 m/s </span>
Answer:
The answer is below
Explanation:
Given that:
mass (m) = 86 kg, distance (L) = 2.75 m, θ = 31°, force (F) = 595 N, initial velocity (
) = 2.4 m/s, g = acceleration due to gravity = 9.8 m/s²
The net work can be gotten from the equation:

From the work-energy theorem equation, we can get her speed at the top of the ramp (
)
Hence:

Answer:
120V
Explanation:
Given parameters:
Current = 6A
Resistance = 20Ω
Unknown:
Voltage = ?
Solution:
According to ohms law;
V = IR
Where V is the voltage
I is the current
R is the resistance
Now, insert the parameters and solve;
V = 6 x 20 = 120V