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2 years ago

Identify the elements that appear before iron (Fe) in the periodic table.

Physics

2 answers:

Vladimir [108]2 years ago

8 0

(Mn) (Cr) (V) (Ti) (Sc) thats it just search it up

maks197457 [2]2 years ago

4 0

The correct answer to the question is : Sc, Ti, V, Cr, Mn.

EXPLANATION:

The given element is iron (Fe).

The atomic number of iron is 26 in the periodic table. It is a transition element which is present at the first transition series i.e in the third row or period in the modern periodic table.

The other transition elements that come in this series before iron is scandium ( Sc), titanium ( Ti), vanadium ( V), chromium ( Cr) and manganese ( Mn) in the periodic table.

There is other two elements that come in the third row which are known as potassium and calcium. But these are not transition group elements.

Hence, the correct answer of this question is Sc, Ti, V, Cr and Mn respectively.

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Hicham El Guerrouj of Morocco holds the world record in the 1500 m running race. He ran the final 400 m in a time of 51.9 s.

konstantin123 [22]

Answer: His average speed in mph over the last 400 m is 7.7 m/s.

Explanation:

Given: Hicham El Guerrouj of Morocco holds the world record in the 1500 m running race. He ran the final 400 m in a time of 51.9 s.

We know that , speed = $\dfrac{distance}{time}$

Here , distance = 400m and time = 51.9 s

Then, speed = $\dfrac{400}{51.9}\approx7.7\ m/s$

Hence, his average speed in mph over the last 400 m is 7.7 m/s.

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2 years ago

Consider a basketball player spinning a ball on the tip of a finger. If a player performs 1.91 J1.91 J of work to set the ball s

Black_prince [1.1K]

Answer:

ω = 4.07 rad/s

Explanation:

By conservation of the energy:

W = ΔK

$1.91J = I/2*\omega^2$

where $I = 2/3*m*R^2=0.23kg.m^2$

Solving for ω:

$\omega = \sqrt{W*2/I} =4.07rad/s$

7 0

2 years ago

A future use of space stations may be to provide hospitals for severely burned persons. it is very painful for a badly burned pe

natta225 [31]

<span>1.5 minutes per rotation. The formula for centripetal force is A = v^2/r where A = acceleration v = velocity r = radius So let's substitute the known values and solve for v. So F = v^2/r 0.98 m/s^2 = v^2/200 m 196 m^2/s^2 = v^2 14 m/s = v So we need a velocity of 14 m/s. Let's calculate how fast the station needs to spin. Its circumference is 2*pi*r, so C = 2 * 3.14159 * 200 m C = 1256.636 m And we need a velocity of 14 m/s, so 1256.636 m / 14 m/s = 89.75971429 s Rounding to 2 significant digits gives us a rotational period of 90 seconds, or 1.5 minutes.</span>

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2 years ago

A charged wire of negligible thickness has length 2L units and has a linear charge density λ. Consider the electric field E-vect

Stels [109]

Answer:

$E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}$

Explanation:

Given that

Length= 2L

Linear charge density=λ

Distance= d

K=1/(4πε)

The electric field at point P

$E=2K\int_{0}^{L}\dfrac{\lambda }{r^2}dx\ sin\theta$

$sin\theta =\dfrac{d}{\sqrt{d^2+x^2}}$

$r^2=d^2+x^2$

$E=2K\lambda d\int_{0}^{L}\dfrac{dx }{(x^2+d^2)^{\frac{3}{2}}}$

Now by integrating above equation

$E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}$

4 0

2 years ago

Janes car uses 1 gallon of petrol for each 40 miles. A gallon of petrol costs 3.20. Work out the cost of petrol for Jane's 320 k

kramer

320 Kilometers = 198.8 miles
I
1 gallon of Petrol = 40 Miles
I
198.8/40 = 4.95 Gallons of Petrol
I
Cost of Petrol = 3:20 (per Gallon) x 4.95 Gallons = 15.84

3 0

2 years ago

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