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olchik [2.2K]
2 years ago
3

What are the advantages and disadvantages of using an egg to model organelles in an animal cell?

Chemistry
1 answer:
garri49 [273]2 years ago
8 0
The advantages of using an egg are:
-Convenient, easily accessible model
-Good representation of cell's ability to retain shape
-Good representation of cell membrane protecting cell's insides
-Yolk is good representation of nucleus, which is large and prominent in the cell
-The egg white accurately represents the cytoplasm, which is also jelly-like


Disadvantages:
-Difficult to discuss other organelles as no other easily visible structures present inside egg
-The inside of the egg is inaccessible and invisible 
-The cell membrane is not as rigid as an egg's shell
You might be interested in
A soda ash is analyzed in the analytical chemistry laboratory by titration with standard hydrochloric acid. The analysis is perf
Gre4nikov [31]

Answer:

93.50±5%

Explanation:

Hello,

The average of the results turns out in 93.50% Na2CO3, thus, the range that the true value lies on is:

93.50±5%

For us to have be 95% confident that we've got the correct result.

Best regards.

6 0
2 years ago
Nitrogen dioxide decomposes to nitric oxide and oxygen via the reaction: 2NO2 → 2NO + O2 In a particular experiment at 300 °C, [
serious [3.7K]

Answer: The rate of disappearance of NO_2 is 3.5\times 10^{-5}M/s

Explanation:

The given chemical reaction is:

2NO_2\rightarrow 2NO+O_2

The rate of the reaction for disappearance of NO_2 is given as:

\text{Rate of disappearance of }NO_2=-\frac{\Delta [NO_2]}{\Delta t}

Or,

\text{Rate of disappearance of }NO_2=-\frac{C_2-C_1}{t_2-t_1}

where,

C_2 = final concentration of NO_2 = 0.00650 M

C_1 = initial concentration of NO_2 = 0.0100 M

t_2 = final time = 100 minutes

t_1 = initial time = 0 minutes

Putting values in above equation, we get:

\text{Rate of disappearance of }NO_2=-\frac{0.00650-0.0100}{100-0}\\\\\text{Rate of disappearance of }NO_2=3.5\times 10^{-5}M/s

Hence, the rate of disappearance of NO_2 is 3.5\times 10^{-5}M/s

6 0
2 years ago
what is the net ionic equation with its physical states? (NH4)2CO3(aq)+Ca(ClO4)2(aq)⟶CaCO3(s)+2NH4ClO4(aq)
Temka [501]

Answer: The net ionic equation is CO_3^{2-}(aq)+Ca^{2+}(aq)\rightarrow CaCO_3(s)

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

(NH_4)_2CO_3(aq)+Ca(ClO_4)_2(aq)\rightarrow CaCO_3(s)+2NH_4ClO_4(aq)

The equation can be written in terms of ions as:

2NH_4^+(aq)+CO_3^{2-}(aq)+Ca^{2+}(aq)+2ClO_4^{-}(aq)\rightarrow CaCO_3(s)+2NH_4^{+}(aq)+2ClO_4^-(aq)

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The ions which are present on both the sides of the equation are ammonium and chlorate ions and hence are not involved in net ionic equation.

Hence, the net ionic equation is :

CO_3^{2-}(aq)+Ca^{2+}(aq)\rightarrow CaCO_3(s)

6 0
2 years ago
which factors are needed to determine the amount of heat absorbed by an aluminum cube after it is warmed? check all that apply
Deffense [45]

Answer:

Explanation:

final temperature of the cube

initial temperature of the cube

mass of the cube

specific heat of aluminum

4 0
2 years ago
Ammonia (nh3(g), hf = –46.19 kj/mol) reacts with hydrogen chloride (hcl(g), hf = –92.30 kj/mol) to form ammonium chloride (nh4cl
steposvetlana [31]

Answer: The \Delta H_{rxn} for the given chemical reaction is -175.51 kJ/mol

Explanation: Enthalpy change of the reaction is defined as the amount of heat released or absorbed in a given chemical reaction.

Mathematically,

\Delta H_{rxn}=\Delta H_f_{(products)}-\Delta H_f_{(reactants)}

We are given a chemical reaction. The reaction follows:

NH_3(g)+HCl(g)\rightarrow NH_4Cl(s)

H_f_{(NH_3)}=-46.19kJ/mol

H_f_{(HCl)}=-92.30kJ/mol

H_f_{(NH_4Cl)}=-314.4kJ/mol

Enthalpy change for the reaction of he given chemical reaction is given by:

\Delta H_{rxn}=H_f_{(NH_4Cl)}-(H_f_{(NH_3)}+H_f_{(HCl)})

Putting the values in above equation, we get

\Delta H_{rxn}=-314.4-(-92.30-46.19)kJ/mol

\Delta H_{rxn}=-175.51kJ/mol

8 0
2 years ago
Read 2 more answers
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