Question

Two of the types of ultraviolet light, uva and uvb, are both components of sunlight. their wavelengths range from 320 to 400 nm for uva and from 290 to 320 nm for uvb. compare the energy of microwaves, uva, and uvb. rank from greatest to least energy per photon. to rank items as equivalent, overlap them.

Answer 1

In light energy, the higher the frequency, the greater the energy a light contain.

We know for a certain that frequency is just the reciprocal of wavelength:

frequency = 1 / wavelength

Calculating for frequencies:

f UVA = 1/320 to 1/400

f UVA = 0.0031 to 0.0025

 

f UVB = 1/290 to 1/320

f UVB = 0.0034 to 0.0031

Since UVB has higher frequency range, then it has higher energy than UVA.

Answer 2

Answer:

uvb > uva > microwaves

Explanation:

The energy of an electromagnetic wave is

$E =\frac{hc}{\lambda}$

Where

h is the Planck's constant

c is the speed of light and

$\lambda$ is the frequency

So we can understand that the energy is inversely proportional to the wavelength

The wavelengths are

1. microwaves - 1 mm - 1m

2. uva - 320 - 400 nm

3. uvb - 290 - 320 nm

So with the smallest wavelength the uvb has the greatest energy

and the microwave has least amount of energy with the largest wavelength range

so the answer is uvb > uva > microwaves