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SIZIF [17.4K]
2 years ago
13

How much heat is removed from the skin by the evaporation of 190 g (about 1/2 cup) of isopropyl alcohol?

Chemistry
1 answer:
Anna35 [415]2 years ago
6 0
The amount of heat removed from the skin is equal to the energy needed by the alcohol to evaporate, which is known as the latent heat of vaporization.

So, you need to know and use the specific latent heat of vaporization of the isopropyl alcohol.

The specific latent heat of vaporization dependes on temperature, but you can use the value of 159 cal / g, which is found in similar problems.

So, now you just need to multiply this specific heat by the amount of alcohol to find the total heat:

Total heat = 190 g * 159 cal / g = 30,210 cal.

Depending on the units you need you likely will have to make a conversion. For example, if you want it in joules you have to diviide by 4.18 cal/joule.
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When one atom loses an electron and another atom accepts that electron a(n) bond between the two atoms results?
morpeh [17]
When an element losses its electron its called a cation. When an element accepted that electron it called anion. This is called an ionic bond.
8 0
2 years ago
When an electron of an atom falls from a higher energy level to the ground state, the atom loses 9.4145 x 10-25 joules of energy
Ann [662]
E = \frac{hc}{wavelength} 

given E = 9.4145E-25
h = 6.626E-34
c = 2.998E8
sub values into the equation above, and solve for wavelength.
You will get 0.211m
3 0
2 years ago
Read 2 more answers
The actual size of a wood louse is 0.4mm but Robert drew his 5mm. What is the magnification?
melomori [17]

Answer:

Magnification is the number of times larger an image is compared with the real size of the object.

Magnification = Image / Actual  = 5/0.4 =12.5

Explanation:

3 0
2 years ago
You've just solved a problem and the answer is the mass of an electron, me=9.11×10−31kilograms. How would you enter this number
irina1246 [14]

Answer: 9.11\times 10^{-31}kg

Explanation:

Significant figures : The figures in a number which express the value or the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures:

Digits from 1 to 9 are always significant and have infinite number of significant figures.

All non-zero numbers are always significant.

All zero’s between integers are always significant.

All zero’s after the decimal point are always significant.

All zero’s preceding the first integers are never significant.

Thus 9.11\times 10^{-31}kg has three significant figures

7 0
2 years ago
Which mass of gas would occupy a volume of 3dm3 at 25°C and 1 atmosphere pressure?
balu736 [363]

Answer:

C 8.09 SO2 gas

Explanation:

As we have the volume (3dm³ = 3L), temperature (25°C + 273 = 298K), and pressure (1atm), we can solve to moles of gas using:

PV = nRT

PV / RT = n

1atm*3L / 0.082atmL/molK*298K =¨

0.123 moles of gas you have.

Now, to convert these moles to mass we use molar mass (32g/mol for O2, 28g/mol for N2, 64g/mol for SO2, and 44g/mol for CO2).

Mass of 0.123 moles of these gases is:

O2 = 0.123 moles * 32g/mol = 3.94g of O2. A is wrong

N2 = 0.123 moles * 28g/mol = 3.4g of N2. B is wrong

SO2 = 0.123 moles * 64.1g/mol = 7.9g of SO2≈ 8.09g of SO2, C is possible

CO2 = 0.123 moles * 44g/mol = 5.4g of CO2. D is wrong

Right answer is:

<h3>C 8.09 SO2 gas </h3>

8 0
2 years ago
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