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JulsSmile [24]
2 years ago
3

If you mechanically shook a mixture of phospholipids and water, what would you expect to see when you observe the solution using

an electron microscope?
Chemistry
2 answers:
serious [3.7K]2 years ago
5 0
You would see that most lipids would almost be completely dissolved in this mixture, This is because the lipids are partially polar.

Goodluck, my friend :-)
Ahat [919]2 years ago
4 0

Answer: two layer liquid (bilayer)

Explanation:

First of all let me explain a few terms

Hydrophobic side: means water disliking part... From the phobia.

Hydrophilic side means water loving side.

So the phospholipid have this two parts. When you shake it in water, the hydrophilic part will interact and mix with water while the hydrophobic part will just float and separated into two layers.. Just like pouring groundnut oil into water.

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Which statement is true about writing chemical formulas of covalent compounds?
Korvikt [17]
Your answer is d hope I helped
4 0
2 years ago
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The element thallium is 70% thallium-205 and 30% thallium-203. Calculate its relative atomic mass to 1 decimal place.
xxMikexx [17]

Answer:

answer-

The relative atomic mass = 204.4

explanation:

Thallium -203 = 30%

Thallium -205 = 70%

Therefore ,

relative mass of thallium = (30×203 + 70×205)/100

relative mass of thallium = (20440)/100

relative mass of thallium = 204.40 amu

Thus,

relative atomic mass of thalium =204.4 ( to 1 decimal place)

6 0
2 years ago
A substance is highly malleable and has a shiny luster. Which of the following best explains the probable position of the substa
Aleks04 [339]
The answer is D only metals are shiny and highly malleable
5 0
2 years ago
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A large cylindrical tank contains 0.750 m3 of nitrogen gas at 27°C and 7.50 * 103 Pa (absolute pressure). The tank has a tight‐f
Nuetrik [128]

Answer: The answer is 68142.4 Pa

Explanation:

Given that the initial properties of the cylindrical tank are :

Volume V1= 0.750m3

Temperature T1= 27C

Pressure P1 =7.5*10^3 Pa= 7500Pa

Final properties of the tank after decrease in volume and increase in temperature :

Volume V2 =0.480m3

Temperature T2 = 157C

Pressure P2 =?

Applying the gas law equation (Charles and Boyle's laws combined)

P1V1/T1 = P2V2/T2

(7500 * 0.750)/27 =( P2 * 0.480)/157

P2 =(7500 * 0.750* 157) / (0.480 *27)

P2 = 883125/12.96

P2 = 68142.4Pa

Therefore the pressure of the cylindrical tank after decrease in volume and increase in temperature is 68142.4Pa

8 0
2 years ago
A compound has the name iodine pentafluoride. What kind of bond is present between the atoms? A. O Metallic B Covalent C. Hydrog
8090 [49]

Answer:

IF(subscript 5)

Explanation:

covalent.

3 0
1 year ago
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