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2 years ago

7

Kishi has a bolt that is 5/8 inch wide and she drilled a hole 0.6 inch wide. is the hole large enough to fit the bolt? explain a

nswer key

1 answer:

nikklg [1K]2 years ago

8 0

when you divide 5 by 8 you get 0.625

since the hole is 0.6

the hole is too small for the bolt to fit

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What is the answer to 13p12=

tiny-mole [99]

Answer:

156p

Step-by-step explanation:

13p×12

multiply the numbers

= 156p

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The amount of bacteria in a Petri dish increases at a rate proportional to the amount present. At time t=0, the amount of bacter

Len [333]

Answer:

C. 270 grams

Step-by-step explanation:

-This is an exponential growth function which can be expressed using the formula:

$P_t=P_oe^{rt}$

Where:

$P_t$ is the size at time t.
$P_o$ is the initial size
$r$ is the growth rate
$t$ is the time

Given the size at t=2 and at t=0, we substitute in the growth function to solve for r:

$30=10e^{2r}\\\\3=e^{2r}\\\\r=\frac{In \ 3}{2}\\\\=0.54931$

We use this calculated rate to determine the population at t=6

$P_t=P_oe^{rt}\\\\=10e^{6\times \frac{In \ 3}{2}}\\\\=270\ grams$

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2 years ago

Which of the following functions is graphed below?

Pavlova-9 [17]

Answer:

D.

Step-by-step explanation:

It is a piece-wise function, so you will have two equations and two different domains. x squared plus 3 represents the sort of parabola and x plus 4 represents a linear function. There is a reason why the point on the parabola is open when x is 4. That open sign means that the x value doesn't work for the equation. Therefore, x cannot be 4 for the parabola and the domain for it is x is less than 4. The point on the linear function is closed to show that 4 for x does work for the equation and graph. For the linear function, the domain for it is x is greater or equal to 4. Hope this helps!

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Solve the equation, keeping the value for x as an improper fraction. 23x = − 12x + 5 1.Isolate the variable by adding 12x to bot

kogti [31]

Answer:

$x=\frac{30}{7}$

Step-by-step explanation:

We have been given an equation $\frac{2}{3}x=-\frac{1}{2}x+5$ . We are asked to solve our given equation.

First of all, we will add $\frac{1}{2}x$ on both sides of equation to separate x variable on one side of equation.

$\frac{2}{3}x+\frac{1}{2}x=-\frac{1}{2}x+\frac{1}{2}x+5$

$\frac{2}{3}x+\frac{1}{2}x=5$

Now, we will make a common denominator.

$\frac{2*2}{3*2}x+\frac{1*3}{2*3}x=5$

$\frac{4}{6}x+\frac{3}{6}x=5$

Add numerators:

$\frac{4+3}{6}x=5$

$\frac{7}{6}x=5$

Upon multiply both sides of our equation by $\frac{6}{7}$ , we will get:

$\frac{6}{7}*\frac{7}{6}x=5*\frac{6}{7}$

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Therefore, the solution for our given equation is $x=\frac{30}{7}$ .

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The height h of the equilateral triangle below is given by y= 5 cot theta where theta = 30 degrees

brilliants [131]

To solve this we can take two different approaches:

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2. We can use the unitary circle and the fact that $cot \alpha = \frac{cos( \alpha }{sin( \alpha )}$ , so we can rewrite our expression as follows:
$y=5cot( \alpha )$
$y=5 \frac{cos( \alpha )}{sin( \alpha )}$
$y= \frac{cos(30)}{sin(30)}$
From our unitary circle we can check that $cos(30)= \frac{ \sqrt{3} }{2}$ and $sin(30)= \frac{1}{2}$ .
Lets replace those values in our expression and simplify:
$y= \frac{ 5(\frac{ \sqrt{3} }{2})}{ \frac{1}{2} }$
$y=5 \sqrt{3}$
$y=8.7$

Either way we can conclude that the correct answer is: D)8.7

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2 years ago