answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
fenix001 [56]
1 year ago
14

a 1.2x10^3 kilogram car is accelerated uniformly from 10. meters per second to 20 meters per second in 5.0 seconds. what is the

magnitude of the net force acting on the car during this 5.0 second interval
Physics
1 answer:
irinina [24]1 year ago
7 0
Force , F = ma

F =  m(v - u)/t               

Where m = mass in kg, v= final velocity in m/s, u = initial velocity in m/s
t = time, Force is in Newton.

m= 1.2*10³ kg,  u = 10 m/s,  v = 20 m/s, t = 5s

F =  1.2*10³(20 - 10)/5

F = 2.4*10³ N = 2400 N


You might be interested in
This is a cell, which is the basic unit of all life. All organs in human bodies are made of cells and require oxygen to survive.
kotegsom [21]
The two systems that work together to deliver oxygen are D, respiratory and cardiovascular
5 0
1 year ago
If gravity between the Sun and Earth suddenly vanished, Earth would continue moving in
Ksenya-84 [330]

Answer:

Earth would continue moving by uniform motion, with constant velocity, in a straight line

Explanation:

The question can be answered by using Newton's first law of motion, also known as law of inertia, which states that:

"an object keeps its state of rest or of uniform motion in a straight line unless acted upon by an external net force different from zero"

This means that if there are no forces acting on an object, the object stays at rest (if it was not moving previously) or it continues moving with same velocity (if it was already moving) in a straight line.

In this problem, the Earth is initially moving around the Sun, with a certain tangential velocity v. When the Sun disappears, the force of gravity that was keeping the Earth in circular motion disappears too: therefore, there are no more forces acting on the Earth, and so by the 1st law of Newton, the Earth will continue moving with same velocity v in a straight line.

6 0
1 year ago
A densly wound cylindrical coil has 210 turns per meter, a 5 cm radius, and carries 38 mA. What is the magnitude of the uniform
kaheart [24]

Answer:

(a). The magnitude of the uniform magnetic field is 10.02 μT

(b). The the magnitude of the total magnetic field is 10.78 μT.

Explanation:

Given that,

Number of turns = 210

Radius = 5 cm

Current = 38 mA

Current in the wire = 500 mA

We need to calculate the magnetic field inside a coil

Using formula of magnetic field

B=\mu_{0} ni

Put the value into the formula

B_{c}=4\pi\times10^{-7}\times210\times38\times10^{-3}

B_{c}=0.0000100\ T

B_{c}=10.02\times10^{-6}\ T

Now a straight wire is inserted into the coil that carries 500 mA. It travels down the central axis of the coil

Distance d=\dfrac{5}{2}

d=2.5\ cm

We need to calculate the magnetic field from the straight wire

Using formula of magnetic field

B_{w}=\dfrac{\mu_{0}I}{2\pi d}

Put the value into the formula

B_{w}=\dfrac{4\pi\times10^{-7}\times500\times10^{-3}}{2\times\pi\times2.5\times10^{-2}}

B_{w}=4.0\times10^{-6}\ T

This field is perpendicular to the wire.

The magnitude of magnetic field is

B=\sqrt{B_{c}^2+B_{w}^2}

B=\sqrt{(10.02\times10^{-6})^2+(4.0\times10^{-6})^2}

B=0.00001078\ T

B=10.78\times10^{-6}\ T

B=10.78\ \mu\ T

Hence, (a). The magnitude of the uniform magnetic field is 10.02 μT

(b). The the magnitude of the total magnetic field is 10.78 μT.

6 0
1 year ago
When you are standing on Earth, orbiting the Sun, and looking at a broken cell phone on the ground, there are gravitational pull
Mandarinka [93]

Answer:

The answer is "Option b, c, and a".

Explanation:

Here that the earth pulls on the phone, as it will accelerate towards Earth when we drop it.

We now understand the effects of gravity:

F \propto  M\\\\F\propto  \frac{1}{r^2}\\\\or\\\\F \propto  \frac{M}{r^2}\\\\Sun (\frac{M}{r^2}) = \frac{10^{28}}{(10^9)^2} = 10^{10}

The force of the sun is, therefore, 10^{10} times greater and the proper sequence, therefore, option steps are:

b. Pull-on phone from earth

c. Pull-on phone from sun

a. Pull phone from you

5 0
1 year ago
12*8A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring 13 feet. The ball is started in
max2010maxim [7]

Answer:

See attached pictures.

Explanation:

See attachments for explanation.

6 0
1 year ago
Other questions:
  • A golf ball is hit by a club. The graph shows the variation with time of the force exerted on the bal
    11·2 answers
  • A raft is made of a plastic block with a density of 650 kg/m 3 , and its dimensions are 2.00 m à 3.00 m à 5.00 m. 1. what is the
    5·1 answer
  • Bats use a process called echolocation to find their food. This involves giving out sound waves that hit possible prey or food.
    7·2 answers
  • A bullet is fired horizontally, and at the same instant a second bullet is dropped from the same height. Ignore air resistance.
    13·1 answer
  • A wind turbine works by slowing the air that passes its blades and converting much of the extracted kinetic energy to electric e
    13·1 answer
  • Light is an oscillating magnetic field alone. an oscillating electric field alone. electric and magnetic fields that oscillate p
    9·1 answer
  • Three point charges are positioned on the x axis. If the charges and corresponding positions are +32 µC at x = 0, +20 µC at x =
    11·1 answer
  • 8. An unpowered flywheel is slowed by a constant frictional torque. At time t = 0 it has an angular velocity of 200 rad/s. Ten s
    7·1 answer
  • Two ice skaters, Paula and Ricardo, initially at rest, push off from each other. Ricardo weighs more than Paula.
    9·1 answer
  • Katie rolls a toy car off the end of a table.
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!