A 0.05-kg car starts from rest at a height of 0.95 m. Assuming no friction, what is the kinetic energy of the car when it reache
s the bottom of the hill? (Assume g = 9.81 m/s2.)
A. 0.466 J
B. 0.308 J
C. 4.317 J
D. 0.0475 J
A. 0.466 J
B. 0.308 J
C. 4.317 J
D. 0.0475 J
2 answers:
The kinetic energy of the car when it reaches the bottom of the hill is about A. 0.466 J
<em>Let's recall </em><em>Kinetic Energy</em><em> Formula as follows:</em>
Ek = Kinetic Energy ( Joule )
m = mass of the object ( kg )
v = speed of the object ( m/s )
Let us now tackle the problem !
<u>Given:</u>
mass of the car = m = 0.05 kg
initial speed of toy car = u = 0 m/s
initial height position of the car = h₁ = 0.95 m
final height position of the car = h₂ = 0 m
gravitational acceleration = g = 9.81 m/s²
<u>Asked:</u>
final kinetic energy of the car = Ek₂ = ?
<u>Solution:</u>
<em>We will use </em><em>Conservation of Energy</em><em> to solve this problem:</em>
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Grade: High School
Subject: Physics
Chapter: Energy
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position 1 = initial height of the diver (h₁), together with the initial velocity (v₁).
position 2 = final height of the diver (h₂) and the final velocity (v₂).
The initial PE = mgh₁ and the initial KE = (1/2)mv₁²
where g = acceleration due to gravity,
m = mass of the diver.
Similarly, the final PE and KE are respectively mgh₂ and (1/2)mv₂².
PE in position 1 is converted into KE due to the loss in height from position 1 to position 2.
Therefore
(KE + PE) ₁ = (KE + PE)₂
Evaluate the given answers.
A) The total mechanical energy of the system increases.
FALSE
B) Potential energy can be converted into kinetic energy but not vice versa.
TRUE
C) (KE + PE)beginning = (KE + PE) end.
TRUE
D) All of the above.
FALSE