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2 years ago

15

A gannet is a seabird that fishes by diving from a great height. part a if a gannet hits the water at 32 m/s , what height did i

t dive from

1 answer:

lutik1710 [3]2 years ago

6 0

93 if this is reasaning but make sure

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An application of this principle is that a line mounted on transparent slide casts the same diffraction pattern as a dark film w

kifflom [539]

Explanation:

It is given that,

The distance between the first spot and the central minimum is, s = 0.007 cm

Length, l = 12 m

Wavelength, $\lambda=6\times 10^{-7}\ m$

We need to find the width of the hair. Using the condition of diffraction pattern as :

$s=\dfrac{m\lambda l}{d}$ , d is the width of the hair

$d=\dfrac{m\lambda l}{s}$

$d=\dfrac{1\times 6\times 10^{-7}\times 12}{0.007}$

d = 0.00102

or

$d=1.02\times 10^{-3}\ m$

So, the width of the hair is $1.02\times 10^{-3}\ m$ . Hence, this is the required solution.

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1 year ago

The force diagram represents a girl pulling a sled with a mass of 6.0 kg to the left with a force of 10.0 N at a 30.0 degree ang

STatiana [176]

the correct answers are 54N and -1,2m/s^2

6 0

1 year ago

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Evaporation of sweat requires energy and thus take excess heat away from the body. Some of the water that you drink may eventual

kotegsom [21]

Answer:

The amount of heat required is $H_t = 1.37 *10^{6} \ J$

Explanation:

From the question we are told that

The mass of water is $m_w = 20 \ ounce = 20 * 28.3495 = 5.7 *10^2 g$

The temperature of the water before drinking is $T_w = 3.8 ^oC$

The temperature of the body is $T_b = 36.6^oC$

Generally the amount of heat required to move the water from its former temperature to the body temperature is

$H= m_w * c_w * \Delta T$

Here $c_w$ is the specific heat of water with value $c_w = 4.18 J/g^oC$

So

$H= 5.7 *10^2 * 4.18 * (36.6 - 3.8)$

=> $H= 7.8 *10^{4} \ J$

Generally the no of mole of sweat present mass of water is

$n = \frac{m_w}{Z_s}$

Here $Z_w$ is the molar mass of sweat with value

$Z_w = 18.015 g/mol$

=> $n = \frac{5.7 *10^2}{18.015}$

=> $n = 31.6 \ moles$

Generally the heat required to vaporize the number of moles of the sweat is mathematically represented as

$H_v = n * L_v$

Here $L_v$ is the latent heat of vaporization with value $L_v = 7 *10^{3} J/mol$

=> $H_v = 31.6 * 7 *10^{3}$

=> $H_v = 1.29 *10^{6} \ J$

Generally the overall amount of heat energy required is

$H_t = H + H_v$

=> $H_t = 7.8 *10^{4} + 1.29 *10^{6}$

=> $H_t = 1.37 *10^{6} \ J$

4 0

2 years ago

To make the jump, Neo and Morpheus have pushed against their respective launch points with their legs applying a _____ to the la

ra1l [238]

Force, newtons 3rd law of motion stated for every action there is an equal and opposite reaction

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1 year ago

A machine is currently set to a feed rate of 5.921 inches per minute (IPM). Te machinist changes this setting to 6.088 IPM. By h

lukranit [14]

Answer:

By 16.7% or 0.167 IPM

Explanation:

Substracting the final IPM (6.088) to the initial IPM (5.921) gives us the net difference, which is how much did it increase in IPM. Multiplying this number by 100 gives us the percentual increase in the feed rate.

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1 year ago

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