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never [62]
2 years ago
9

In football a kicker can score one point for the extra point on a touchdown or three points for a field goal Logan is a kicker f

or his high school football team the record number of points scored by a kicker in a single game is 24 Logan is hoping to beat this record in his next game
Write a linear inequality to represent this situation then graph

Mathematics
2 answers:
mezya [45]2 years ago
8 0
Let the number of extra points on a touchline scored by Logan on the match be x and the number of field goals scored by Logan be y, then the ineaquality representing the situation wher Logan beats the record number of points scored by a kicker in a single match of 24 is given by:

x + 3y > 24

The graph is attached

Alex777 [14]2 years ago
5 0

Answer:

Let the number of extra points on a touchline scored by Logan on the match be x and the number of field goals scored by Logan be y, then the ineaquality representing the situation wher Logan beats the record number of points scored by a kicker in a single match of 24 is given by:

x + 3y > 24

Step-by-step explanation:

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G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =
Svetach [21]
Presumably you should be doing this using calculus methods, namely computing the surface integral along \mathbf r(u,v).

But since \mathbf r(u,v) describes a sphere, we can simply recall that the surface area of a sphere of radius a is 4\pi a^2.

In calculus terms, we would first find an expression for the surface element, which is given by

\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv

\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k
\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j
\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k
\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u

So the area of the surface is

\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u
=-2\pi a^2(\cos\pi-\cos 0)
=-2\pi a^2(-1-1)
=4\pi a^2

as expected.
6 0
2 years ago
Which polynomials are listed with their correct additive inverse ? Check all that apply . x^ 2 +3x-2;-x^ 2 -3x+2 O -y^ 7 -10;-y^
Phoenix [80]

Answer:

a, c. and d

Step-by-step explanation:

5 0
2 years ago
Two towns, A and B, are connected by a road. At sunrise, Pat begins biking from A to B along this road, while simultaneously Dan
Gnoma [55]

Answer:

The answer is "4.5"

Step-by-step explanation:

Given value:

\text{time = 11:15 PM}

formula:

\to t^2=\frac{pt}{D} \times \frac{Dt}{P}\\\\_{where}\\\\\text {t= time = noon - sunrise}\\\\\text{p= pat's speed}\\\\\text{D= Dana's speed}\\

\to t^2= 11.25 \times 5\\\\

      = 56.25\\\\

\to t= 7.5

if the sunrise value is =12

\to sunrise = 12- 7.5

                 = 4.5

3 0
2 years ago
A client would like a logo printed onto a canvas that is at least 70 inches tall. The original logo is 4.5 inches wide by 3.6 in
Valentin [98]

Answer:

to find the dimension I would get 3.6/4.5=x/70 amd u get 3.6*70=4.5x and u get 252=4.5x and x=56

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Ken grew 4/5 of an inch last year. sang grew3/8 of an inch . who grew more and by how much?
Licemer1 [7]
Sang grew more. and by 17/40 ( I could be wrong)
4 0
2 years ago
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