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shtirl [24]
1 year ago
13

A 108 49in source emits a 633-kev gamma photon and a 606-kev internal-conversion electron from the k shell. what is the binding

energy of the electron in the k shell?
Chemistry
1 answer:
____ [38]1 year ago
6 0
Binding energy is the energy needed to emit the electron from the shell. Using the formula below to compute for BE. Binding Energy BE = Energy of photon - Kinetic energy electron
where 
Energy proton= 633 keV
KE electron = 606 keV
Binding energy BE = 27 keVThe binding energy of the k subshell is equal to 27 keV.

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HCl Acid + Sodium Hydroxide ----> Sodium  Chloride + water.

<u>Explanation</u>:

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Material A has a small latent heat of fusion. Material B has a large heat of fusion. Which of the following statements is true?
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1 year ago
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Mario uses a hot plate to heat a beaker of 50mL of water. He used a thermometer to measure the temperature of the water. The wat
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If a large marshmallow has a volume of 2.75 in3 and density of 0.242 g/cm3, how much would it weigh in grams? 1 in3=16.39 cm3.
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<span>
•   </span>Volume of the marshmallow:

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V = 2.75 × 16.39 cm^3

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<span>•  </span>Mass:

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m = (0.242 g/cm^3) × (45.0725 cm^3)

m = 10.907545 g

m ≈ 10.9 g   <——<span>—  this is the answer.


I hope this helps. =)
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