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shtirl [24]
2 years ago
13

A 108 49in source emits a 633-kev gamma photon and a 606-kev internal-conversion electron from the k shell. what is the binding

energy of the electron in the k shell?
Chemistry
1 answer:
____ [38]2 years ago
6 0
Binding energy is the energy needed to emit the electron from the shell. Using the formula below to compute for BE. Binding Energy BE = Energy of photon - Kinetic energy electron
where 
Energy proton= 633 keV
KE electron = 606 keV
Binding energy BE = 27 keVThe binding energy of the k subshell is equal to 27 keV.

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Hello,

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IF(subscript 5)

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