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VladimirAG [237]

2 years ago

6

A car travels three-quarters of the way around a circle of radius 20.0 m in a time of 3.0 s at a constant speed. the initial vel

ocity is west and the final velocity is south. (a) find its average velocity for this trip. (b) what is the car's average acceleration during these 3.0 s? (c) explain how a car moving at constant speed has a nonzero average acceleration.

1 answer:

schepotkina [342]2 years ago

3 0

20.3 divided by 3.0 will get u velocity and v times 3.0s

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One component of a metal sculpture consists of a solid cube with an edge of length 38.9 cm. The alloy used to make the cube has

vovangra [49]

Answer:

The mass of the cube is 420.8 kg.

Explanation:

Given that,

Length of edge = 38.9 cm

Density $\rho= 7.15 \times10^{3}\ kg/m^3$

We need to calculate the volume of cube

Using formula of volume

$V = 38.9^3$

$V=0.058863\ m^3$

We need to calculate the mass of the cube

Using formula of density

$\rho = \dfrac{m}{V}$

$m = V\times\rho$

$m =0.058863\times7.15 \times10^{3}$

$m=420.8\ kg$

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7 0

1 year ago

At a local swimming pool, the diving board is elevated h = 5.5 m above the pool's surface and overhangs the pool edge by L = 2 m

Margaret [11]

Answer:

Part a)

$t = \sqrt{\frac{2h}{g}}$

Part b)

$t = 1.06 s$

Part c)

$L = 4.86 m$

Explanation:

Part a)

The height of the diving board is given as

$h = 5.5 m$

now the speed of the diver is given as

$v_0 = 2.7 m/s$

when the diver will jump into the water then his displacement in vertical direction is same as that of height of diving board

So we will have

$y = v_y t + \frac{1}{2}at^2$

$h = 0 + \frac{1}{2}gt^2$

$t = \sqrt{\frac{2h}{g}}$

Part b)

$t = \sqrt{\frac{2h}{g}}$

plug in the values in the above equation

$t = \sqrt{\frac{2(5.5 m)}{9.81}$

$t = 1.06 s$

Part c)

Horizontal distance moved by the diver is given as

$d = v_0 t$

$d = 2.7 \times 1.06$

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so the distance from the edge of the pool is given as

$L = 2.86 + 2$

$L = 4.86 m$

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1 year ago

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Answer:

The flux is 682.6 Wb.

Explanation:

Given that,

Vector field $F=-6i+5x^2j-5k$

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Explanation:

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Answer:

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Explanation:

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