I’d say option 3
Good luck!
Answer:
The answer is A.
Step-by-step explanation:
You have to elaborate it :


Answer:
y-intercept of the line MN = 2
Standard form of the equation ⇒ x + y = 2
Step-by-step explanation:
Coordinates of the ends of a line MN → M(-3, 5) and N(2, 0)
Slope of a line = 
= 
= -1
Equation of the line MN passing through (-3, 5) and slope = -1,
y - 5 = (-1)(x + 3)
y - 5 = -x - 3
y = -x + 2
This equation is in the y-intercept form,
y = mx + b
where m = slope of the line
b = y-intercept
Therefore, y-intercept of the line MN = 2
Equation in the standard form,
x + y = 2
Answer:
Step-by-step explanation:
Rate of leakage, R(t) = 1400 e^0.06t gallons/h
fraction remains , S(t) = e^(-0.32t)
initial contaminant = 1000 gallon
gallons contaminant present after t hour is S(t) R(t)
G(t) = S(t) R(t)


Put t = 18 hours

Taking log on both the sides
ln G = ln 1400 - 0.26 x 18
ln G = 7.244 - 4.68
ln G = 2.564
G = 13 gallons
Answer:
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
A = 84 mg