Average acceleration: ( v - v o ) / Δ t
v = 0 m/s, v o = 20 m/s, Δ t = 3.5 s
a (average) = ( 0 m/s - 20 m/s )/3.5 s = - 20 m/s / 3.5 s =
= - 5.7142857 m/s² ≈ - 5.71 m/s²
To factor completely 18b - 32, we factor out the common factor of the two terms and divide each of term by the common factor.
18b - 32 = 2(18b/2 - 32/2) = 2(9b - 16)
Answer:
speed of Jada = 6km per hour which is not equal to
speed of Andre = 8km per hour
They did not run at same speed
Step-by-step explanation:
formula of speed = distance covered/ time taken
For Andre
Distance = 2 KM
time = 15 mins
60 mins = 1 hour
15 mins = 1/60 * 15 hour = 0.25 hours
thus,
speed = 2km/0.25 hour = 8 km per hour
Similarly for Jada
Distance = 3 KM
time = 20 mins
60 mins = 1 hour
20 mins = 1/60 * 20 hour = 1/3 hours
thus,
speed = 2km/(1/3)hour = 6 km per hour
Now we have
speed of Jada = 6km per hour which is not equal to
speed of Andre = 8km per hour
