answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lbvjy [14]
2 years ago
12

A ball is launched with initial speed v from the ground level up a frictionless hill. the hill becomes steeper as the ball slide

s up; however, the ball remains in contact with the hill at all times. using conservation of energy, find the maximum vertical height hmax to which the ball will climb. express your answer in terms of v and g.
Physics
2 answers:
yulyashka [42]2 years ago
8 0

The ball will rise to a maximum height of \boxed{h=\dfrac{v^2}{2g}}.

Explanation:

The kinetic energy of a body is the energy associated with the body by virtue of its motion whereas the potential energy of the body is the amount of energy stored in a body by virtue of its position.

The amount of kinetic energy stored in a body is given by:

\boxed{K=\dfrac{1}{2}mv^2}                                                ...... (1)

Here, K is the kinetic energy, m is the mass and v is the speed of the body.

The potential energy stored in a body as it reaches its maximum height is given as:

\boxed{P=mgh}                                                      ...... (2)

Here, P is the potential energy stored, g is the acceleration due to gravity and h is the height attained by the body.

According to the conservation of energy, the energy can neither be created nor destroyed. It can only be converted from one form to another.

\text{kinetic energy}=\text{potential energy}

Substitute the values of kinetic energy and potential energy and simplify the expression for the maximum height.

\begin{aligned}\dfrac{1}{2}mv^{2}=&mgh_{max}\\h_{max}=&\dfrac{v^2}{2g}\end{aligned}

Therefore, the maximum height attained by the ball as it rises up is \boxed{h_{max}=\dfrac{v^2}{2g}}.

Learn More:

1. The speed of the quarterback after he throws the ball brainly.com/question/1933971

2. Average power created by the force acting on the sled to move it brainly.com/question/465528

3. The work done on the gas to expand at a constant pressure brainly.com/question/2351427

Answer Details:

Grade: Senior School

Subject: Physics

Chapter: Conservation of Energy

Keywords:

Ball is launched, ground level, conservation of energy, kinetic, potential energy, motion, maximum height, in contact with hill, vertical height, in terms of v and g.

frutty [35]2 years ago
4 0
<span>if we take ball then the Kinetic Energy of the ball is ½mV² as it rolls up the slope, the Kinetic Energy is converted to potential energy, PE = mgh. mgh = ½mV² h = V²/2g</span>
You might be interested in
A boy of mass 80 kg slides down a vertical pole, and a frictional force of 480 N acts on him. What is his acceleration as he sli
olga_2 [115]

Answer:

His acceleration is \overrightarrow{a}=4\frac{m}{s^{2}}

Explanation:

Newton's second law states that acceleration of a body is cause by a net force, the relation between them is:

\sum\overrightarrow{F}=m\overrightarrow{a}

On the boy there're acting two forces, his weight (W) that points downward and the frictional force (f) that points upward (they boy moves downward and friction always is opposite to movement). So \sum\overrightarrow{F}=\overrightarrow{W}+\overrightarrow{f} so (1) is:

\overrightarrow{W}+\overrightarrow{f}=m\overrightarrow{a}

Using the positive direction downward weight and gravitational acceleration(g) are positive and friction force is negative:

W-f=m\overrightarrow{a}, solving for a:

\overrightarrow{a}=\frac{W-f}{m}, weight is mg:

\overrightarrow{a}=\frac{mg-f}{m}=\overrightarrow{f}=\frac{(80kg)(10\frac{m}{s^{2}})-(480)}{80}

\overrightarrow{a}=4\frac{m}{s^{2}}

6 0
2 years ago
A brick is resting on a rough incline as shown in the figure. The friction force acting on the brick, along the incline, is
Tasya [4]
B) equal to the gravitational force of the brick
6 0
2 years ago
Read 2 more answers
A vertical spring of constant k = 400 N/m hangs at rest. When a 2 kg mass is attached to it, and it is released, the spring exte
Viefleur [7K]

Answer:

4.9 cm

Explanation:

From Hook's Law,

F = ke......................... Equation 1

Where F= force, e = extension, k = spring constant.

Note: the Force acting on the the spring is the weight of the mass.

W = mg.

F = mg.................... Equation 2

Where m = mass, g = acceleration due to gravity

Substitute equation 2 into equation 1

mg = ke

make e the subject of the equation

e = mg/k............... Equation 3.

Given: m = 2 kg, g = 9.8 m/s², k = 400 N/m

e = (2×9.8)/400

e = 19.6/400

e = 0.049 m

e = 4.9 cm

3 0
2 years ago
Hydrogen (H-1), deuterium (H-2), and tritium (H-3) are the three isotopes of hydrogen. What are the values of a, b, and c in the
asambeis [7]

I believe it is a=1 b=2 c=3

plato students

6 0
2 years ago
Read 2 more answers
A woman fires a rifle with barrel length of 0.5400 m. Let (0, 0) be where the 125 g bullet begins to move, and the bullet travel
dybincka [34]

Answer:

Explanation:

Given that,

Length of barrel =0.54m

Mass of bullet=125g=0.125kg

Force extend

F=16,000+10,000x-26,000x²

a. Work done is given as

W= ∫Fdx

W= ∫(16,000+10,000x-26,000x² dx from x=0 to x=0.54m

W=16,000x+10,000x²/2 -26,000x³/3 from x=0 to x=0.54m

W=16,000x+5,000x²- 8666.667x³ from x=0 to x=0.54m

W= 16,000(0.54) + 5000(0.54²) - 8666.667(0.54³) +0+0-0

W=8640+1458-1364.69

W=8733.31J

The workdone by the gas on the bullet is 8733.31J

b. Work done is given as

Work done when the length=1.05m

W= ∫Fdx

W= ∫(16,000+10,000x-26,000x² dx from x=0 to x=1.05m

W=16,000x+10,000x²/2 -26,000x³/3 from x=0 to x=1.05m

W=16,000x+5,000x²- 8666.667x³ from x=0 to x=1.05mm

W= 16,000(1.05) + 5000(1.05²) - 8666.667(1.05³) +0+0-0

W=16800+5512.5-10032.75

W=12,279.75J

The workdone by the gas on the bullet is 12,279.75J

3 0
2 years ago
Other questions:
  • A 5 inch tall balloon shoot doubles in height every 3 days. if the equation y=ab^x, where is x is the number of doubling periods
    10·1 answer
  • A stone tumbles into a mine shaft strikes bottom after falling for 4.2 seconds. How deep is the mine shaft
    5·1 answer
  • Four students measured the acceleration of gravity. The accepted value for their location is 9.78 m/s2. Which student's measurem
    9·2 answers
  • Jin walked 4 km on a straight path to get to the sandwich shop. He traveled 30° south of east.
    10·2 answers
  • A 15.0-Ω resistor and a coil are connected in series with a 6.30-V battery with negligible internal resistance and a closed swit
    14·1 answer
  • A stiff wire bent into a semicircle of radius a is rotated with a frequency f in a uniform magnetic field, as suggested in Fig.
    13·1 answer
  • A plane wave with a wavelength of 500 nm is incident normally on a single slit with a width of 5.0 x 10–6 m. Consider waves that
    6·2 answers
  • There are many well-documented cases of people surviving falls from heights greater than 20.0 m. In one such case, a 55.0 kg wom
    7·1 answer
  • A uniform stationary ladder of length L = 4.5 m and mass M = 11 kg leans against a smooth vertical wall, while its bottom legs r
    12·1 answer
  • Think of something from everyday life that follows a two-dimensional path. It could be a kicked football, a bus that's turning a
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!