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2 years ago

If the ph of a solution is decreased from ph 8 to ph 6 it means that the

2 answers:

8 0

If the pH of a solution is decreased from pH 8 to pH 6 it means that the concentration of hydrogen ions in the solution has been increased while the concentration of OH ions have been decreased.

<h2>Further Explanation: </h2><h3>pH and pOH </h3>

pH and pOH measures the acidity or alkalinity of a substance.
pH is the measure hydrogen ion concentration in a substance while pOH measures the concentration of hydroxyl ions.

<h3>Acids and bases </h3><h3>Acids </h3>

Acids are substances that react with bases to form salt and water as the only products.
Acids have a pH less than 7, with strong acids having a pH range of 1-3 while weak acids have a pH range of 4-6.
The pOH of acids on the other hand is greater than 7.

<h3>Bases</h3>

Bases are substances that react with acids to form salt and water as the only product.
Bases have a pH greater than 7, with strong bases having a pH range of 12-14 and weak bases having a pH range of 8-11.
Bases have a pOH less than 7.

<h3>Calculation of pH and pOH </h3>

pH is calculated as the negative logarithm of hydrogen ion concentration.

That is;

pH = -Log [H+]

pOH on the other hand is calculated as the negative logarithm of hydroxyl ion concentration.

That is;

pOH =-Log[OH-]

Additionally;

pH + pOH = 14

Keywords: Acids, bases, pH, pOH

<h3>Learn more about:</h3>

pH :brainly.com/question/10951922
pOH : brainly.com/question/10951922
Example of a question on pH: brainly.com/question/10951922
Example of a question on pOH: brainly.com/question/10951922

Level; High school

Subject: Chemistry

Topic: Acids and bases

Sub-topic; pH and pOH

saw5 [17]2 years ago

5 0

Explanation:

Relation between pH and concentration of hydrogen ions is as follows.

pH = $-log [H^{+}]$

So, it means that an increase in the value of pH will show that there occurs a decrease in concentration of hydrogen ions.

Therefore, the solution becomes basic in nature.

On the other hand, a decrease in the value of pH will show that there occurs an increase in the concentration of hydrogen ions.

Therefore, the solution becomes more acidic in nature.

Hence, if the pH of a solution is decreased from pH 8 to pH 6 it means that the concentration of hydrogen ions has increased in the solution.

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Answer:

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Using Boyle's law

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Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${1.0\ atm}\times {3.6\ L}={13.3\ atm}\times {V_2}$

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2 years ago

How many moles of BCl3 are needed to produce 10.0 g of HCl(aq) in the following reaction? (HCl molar mass is 36.46 g/mol).

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Answer:

Moles of BCl₃ needed = 0.089 mol

Explanation:

Given data:

Moles of BCl₃ needed = ?

Mass of HCl produced = 10.0 g

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Chemical equation:

BCl₃ + 3H₂O → 3HCl + B(OH)₃

Number of moles of HCl:

Number of moles = mass/molar mass

Number of moles = 10.0 g/ 36.46 g/mol

Number of moles = 0.27 mol

Now we will compare the moles of HCl with BCl₃.

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2 years ago

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<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=9.06g$

Mass of $H_2O=5.58g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 9.06 g of carbon dioxide, $\frac{12}{44}\times 9.06=2.47g$ of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 5.58 g of water, $\frac{2}{18}\times 5.58=0.62g$ of hydrogen will be contained.

Mass of oxygen in the compound = (6.38) - (2.47 + 0.62) = 3.29 g

To formulate the empirical formula, we need to follow some steps:

<u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{2.47g}{12g/mole}=0.206moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.62g}{1g/mole}=0.62moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{3.29g}{16g/mole}=0.206moles$

<u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.206 moles.

For Carbon = $\frac{0.206}{0.206}=1$

For Hydrogen = $\frac{0.62}{0.206}=3$

For Oxygen = $\frac{0.206}{0.206}=1$

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 3 : 1

Hence, the empirical formula for the given compound is $C_1H_{3}O_1=CH_3O$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

We are given:

Mass of molecular formula = 124 amu = 124 g/mol

Mass of empirical formula = 31 g/mol

Putting values in above equation, we get:

$n=\frac{124g/mol}{31g/mol}=4$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 4)}H_{(3\times 4)}O_{(1\times 4)}=C_4H_{12}O_4$

Thus, the empirical and molecular formula for the given organic compound is $CH_3O$ and $C_4H_{12}O_4$

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2 years ago