Answer:
t = 6,485 s
, t_step = 25.94 s
the elephant gives 2.3 step very minute
Explanation:
Let's approximate this system to a simple pendulum that has angular velocity
w = √L / g
Angular velocity and period are related
w = 2π / T
T = 2π √g / L
Let's find the period
T = 2π √9.8 / 2.3
T = 12.97 s
Stride time is
t = T / 2
t = 12.97 / 2
t = 6,485 s
Frequency is inversely proportional to period
f = 1 / t
f = 1 / 6,485
f = 0.15 Hz
Since the elephant has 4 legs and each uses a time t, the total time for one step is
t_step = 4 t
t_step = 4 6.485
t_step = 25.94 s
f_step = 1/t_step =0.0385 s-1
Now let's use a proportion rule to find the number of steps in 60 s
#_step = 60 / t_step
#__step = 60 / 25.94
#_step = 2.3 steps
So the elephant gives 2.3 step very minute
Answer:
720 J
Explanation:
The gravitational potential energy that Essam loses for every metre is given by:

where
m=72 kg is Essam's mass
is the gravitational field strength
is the difference in height
By substituting the numbers into the formula, we find

Answer: 2R
Explanation:
Here the person travels пR distance. We know that the circumference of a circle is 2πR. So your imaginated person has traveled the distance which is half of the circumference of the circle. And this distance is equal to its diameter. We know that diameter of a circle is two times larger than the radius. So the person's displacement is two times of the radius, means 2R. [Here 'R' means the radius of the circle]
Answer:
Fa=774 N
Fb=346 N
Explanation:
We will solve this problem by equating forces on each axis.
- On x-axis let forces in positive x-direction be positive and forces in negative x-direction be negative
- On y-axis let forces in positive y-direction be positive and forces in negative y-direction be negative
While towing we know that car is mot moving in y-direction so net force in y-axis must be zero
⇒∑Fy=0
⇒
⇒
⇒
Given that resultant force on car is 950N in positive x-direction
⇒∑Fx=950
⇒
⇒
⇒
⇒
⇒
⇒ 
⇒


Therefore approximately, Fa=774 N and Fb=346 N
Answer:
Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.
Explanation:
Since Juan is closer to the center and Kuri is away from the center so we can say that Juan will move smaller distance in one complete revolution
As we know that the distance moved in one revolution is given as

also the time period of revolution for both will remain same as they move with the time period of carousel
Now we can say that the speed is given as

so Juan will have less tangential speed. so correct answer will be
Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.