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dmitriy555 [2]
2 years ago
8

A power source supplies a prescribed voltage and is used to power a light bulb if another light bulb is connected in series to t

he first how would it affect the current in the power source?.
Physics
2 answers:
pychu [463]2 years ago
8 0
<span>The current from the power source will not change when the second light bulb is attached. This is because the current is kept on a single path, it will return to the power source at the same value it left the source at.</span>
alexira [117]2 years ago
6 0

Answer: It would decrease.

Explanation:

From Ohm's law:

I = V/R

I = current

V = voltage

R = Resistance

The power source supplies a fixed voltage (V). Let the resistance of each light bulb be R.

When a light bulb is connected across voltage V, current I = V/R flows in the circuit.

When another bulb is added in series, the net resistance increases:

R' = R + R = 2 R

Because of increase in resistance, the current drawn in circuit decreases.

⇒ I' = V/2 R = I/2

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1) A capacitor consists of two metal surfaces separated by an electrical insulator with no electrically conductive path through
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Answer:

Current flows in a resistor-capacitor circuit because of the varying electric field across the plates of a capacitor induced by an AC voltage source <em>(displacement current)</em>

Explanation:

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2 years ago
A 248-g piece of copper is dropped into 390 mL of water at 22.6 °C. The final temperature of the water was measured as 39.9 °C.
Sedaia [141]

Answer:

335°C

Explanation:

Heat gained or lost is:

q = m C ΔT

where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.

Heat gained by the water = heat lost by the copper

mw Cw ΔTw = mc Cc ΔTc

The water and copper reach the same final temperature, so:

mw Cw (T - Tw) = mc Cc (Tc - T)

Given:

mw = 390 g

Cw = 4.186 J/g/°C

Tw = 22.6°C

mc = 248 g

Cc = 0.386 J/g/°C

T = 39.9°C

Find: Tc

(390) (4.186) (39.9 - 22.6) = (248) (0.386) (Tc - 39.9)

Tc = 335

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