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Over [174]
2 years ago
11

The iron ball shown is being swung in a vertical circle at the end of a 0.7-m string. how slowly can the ball go through its top

position without having the string go slack?
Physics
1 answer:
marta [7]2 years ago
6 0
<span>A centripetal force is a force which keeps an object moving in a circle. When the ball is at the top position, let's assume that the speed v is such that the gravitational force is precisely equal to the required centripetal force to keep the ball moving around in a circle. Then the string will not go slack. centripetal force = force of gravity on the ball m v^2 / r = m g v^2 / r = g v^2 = g r v = sqrt { g r } v = sqrt { (9.80~m/s^2) (0.7 m) } v = 2.62 m/s The minimum speed of the ball at the top position is 2.62 m/s</span>
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A bobsled is pushed with a force of 190.08 N. The sled has a mass of 28 kg. What is the acceleration of the bobsled? Report to t
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By definition it is known that force equals mass by acceleration. In other words F = m * a. To find the acceleration, you must clear the formula mentioned. Therefore, for a force of 190.08N and a mass of 28 Kg, we have that the acceleration is a = F / m = (190.08) / (28) = 6.79 m / s ^ 2
6 0
2 years ago
A mercury thermometer has a glass bulb of interior volume 0.100 cm3 at 10°c. the glass capillary 10) tube above the bulb has an
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Initial volume of mercury is
V = 0.1 cm³

The temperature rise is 35 - 5 = 30 ⁰C = 30 ⁰K.

Because the coefficient of volume expansion is 1.8x10⁻⁴ 1/K, the change in volume of the mercury is 
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The cross sectional area of the tube is
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h = ΔV/A
   = (5.4x10⁻⁴ cm³)/(0.012x10⁻² cm²)
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Answer: 4.5 cm
7 0
2 years ago
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the first one is medium, the second one is type, and the third one is temperature . if i gave the correct answer, please give best answer x

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2 years ago
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Question 8 (4 points)
katrin2010 [14]

Answer:

The answer to your question is:

Explanation:

Data

Duane                                          Albert

d = 5 m ;  v = 3 m/s                     v = 4.2 m/s

a)                                                b)

Duane's                                      Albert's

d = 5 + (3)t                                  d = 4.2t

d = 5 + 3t

c)                            5 + 3t = 4.2t

                              4.2t - 3t = 5

                                      1.2t = 5

                                           t = 4.17 s

d)

Duane's

d= 5 + 3(4.17)

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Alberts

d = 4.2(4.17)

d = 17.51 m

4 0
2 years ago
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Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. A 9.4 kg gibbon
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Answer:

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Explanation:

given,

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                        = 261.6 N

upward force acting = 261.6 N

7 0
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