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spin [16.1K]
2 years ago
11

"a very light ideal spring stretches by 21.0 cm when it is used to hang a 135-n object. what is the weight of a piece of electro

nic equipment that would stretch the spring 44.9 cm by if you hung the equipment using the spring?
Physics
2 answers:
Olin [163]2 years ago
6 0
In the first scenario, upon reaching equilibrium
       mg = kx
      135 = k(0.21) [Converted x in SI units]
          k = 135/(0.21)

Similarly, in the second scenario, upon reaching equilibrium
       mg = kx
       mg = [(135)(.449)]/(0.21)
       mg = weight of the electronic equipment = 289 N(approx)
hjlf2 years ago
3 0

Answer:

F= 288.7 N

Explanation:

Hooks Law

"states that the strain/deformation of an elastic object or material is proportional to the stress applied to it."

From Hooke's Law we can determine the spring constant  

F = k*x  

so

k = F/x  

k=  135N/.21m

k= 643 N/m

So  if a fish stretches the spring 0.449m  then it would weigh  

F =k*x

F= 643N/m*0.449m

F= 288.707 N

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Which of the following substances will show the smallest change in temperature when equal amounts of energy are absorbed?
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m_a_m_a [10]
Let us assume the upstream rowing rate of Alicia = x
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The maximum tension that a 0.80 m string can tolerate is 15 N. A 0.35-kg ball attached to this string is being whirled in a vert
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Answer:

v=5.86 m/s

Explanation:

Given that,

Length of the string, l = 0.8 m

Maximum tension tolerated by the string, F = 15 N

Mass of the ball, m = 0.35 kg

We need to find the maximum speed the ball can have at the top of the circle. The ball is moving under the action of the centripetal force. The length of the string will be the radius of the circular path. The centripetal force is given by the relation as follows :

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a 4357 kg roller coaster car starts from rest at the top of a 36.5 m high track. determine the speed of the car at the top of a
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