Answer:
The correct answer is 5.6 × 10⁻²³ M.
Explanation:
As a highly soluble salt, KBr dissolves easily in water, while Hg₂Br₂ is very less soluble in comparison to KBr.
Let the solubility of Hg₂Br₂ is S mol per liter.
Therefore,
KBr (s) (1.0 M) ⇒ K⁺ (aq) (1M) + Br⁻ (aq) (1M)
Hg₂Br₂ (s) (1-S) ⇔ Hg₂⁺ (aq) (S) + 2Br⁻ (aq) (2S)
Net [Br-] = (2S + 1) M
Ksp = S (2S + 1)²
Ksp = S (4S² + 1 + 4S)
Ksp = 4S³ + S + 4S²
As the solubility is extremely less, therefore, we can ignore S² and S³. Now,
Ksp = S = 5.6 × 10⁻²³ M
Hence, the solubility of Hg₂Br₂ is 5.6 × 10⁻²³ M.
Carbonated water would be what you are looking for :v)
<span>Use the Arrhenius equation. Use p1 and p2 and T1 and T2 and solve for Ea (actgivation energy) in Joules, then plug that back into the Arrhenius equation and either p1 or p2 to calculate p at 25C.</span>
Answer:
a. 95.35 L b. 20.52 L c. 19.07 L
Explanation:
Hello,
In the attached picture, you will find the solution for this exercise.
Take into account that for the Redllich-Kwong volume, a cubic polynomial must be solved to get the roots, thus, two roots are complex and one contains the molar volume which is converted to the volume I am showing.
In the following link you will find the corresponding states graph I used: https://www.slideserve.com/taipa/che-201-introduction-to-chemical-engineering
Best regards.
Answer:

Explanation:
Hello!
In this case, considering the given chemical reaction and the mass of the magnesium strip, following the indications of the atomic weight ratio (2.61 g Cu/1 g Mg), and keeping in mind the 1:1 mole ratio one could compute the produced mass of copper as shown below:

Best regards!