An ideal gas has a density of 1.75 kg/m3 at a gauge pressure of 160 kPa. What must be the gauge pressure if a density of 1.0 kg/
2 answers:
You might be interested in
Answer:
F = - 59.375 N
Explanation:
GIVEN DATA:
Initial velocity = 11 m/s
final velocity = 1.5 m/s
let force be F
work done = mass* F = 4*F
we know that
Change in kinetic energy = work done
kinetic energy =
kinetic energy = = -237.5 kg m/s2
-237.5 = 4*F
F = - 59.375 N
To solve this exercise it is necessary to apply the kinematic equations of angular motion.
By definition we know that the displacement when there is constant angular velocity is
From our given data we know that,
Moreover we know that
Therefore for time t=8.1s we have,
That number in revolution is:
Here, we see that there are 15 complete revolutions
And 0.108 revolutions i not complete, so the tunable rotation is
Therefore the angle of the speck at a time 8.1s is
Answer:
The angular magnification is
Explanation:
From the question we are told
The focal length is
The near point is
The angular magnification is mathematically represented as
Substituting values