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sergeinik [125]

2 years ago

8

Given: ΔABC with Prove: Statement Reason 1. given 2. Addition Property of Equality 3. using common denominators 4. AB = AD + DB

CB = CE + EB segment addition 5. Substitution Property of Equality 6. ∠ABC ≅ ∠DBE Reflexive Property of Congruence 7. ΔABC ~ ΔDBE SAS similarity criterion 8. Corresponding angles of similar triangles are congruent. 9. If the corresponding angles formed by two lines cut by a transversal are congruent, then the lines are parallel. Question 19 of 44 What is the missing step in this proof? ∠BAC ≅ ∠ACB ∠BDE ≅ ∠DEB ∠ADE ≅ ∠DEC ∠BAC ≅ ∠BDE ∠ABC ≅ ∠DBE NextReset

2 answers:

Aliun [14]2 years ago

8 0

Answer:

AD/DB+1=CE/EB+1

Addition Property of Equality

Step-by-step explanation:

11111nata11111 [884]2 years ago

5 0

Answer:

AD/DB+1=CE/EB+1

Addition Property of Equality

Step-by-step explanation:

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Triangle PQR with vertices P(3, −6), Q(6, −9), and R(−15, 3) is dilated by a scale factor of 3 to obtain triangle P′Q′R′. Which

vovangra [49]

Answer:

Option C.

Step-by-step explanation:

The vertices of triangle PQR are P(3, −6), Q(6, −9), and R(−15, 3).

It is given that triangle PQR dilated by a scale factor of 3 to obtain triangle P′Q′R′.

We know that a figure and its image after dilation are similar. It means triangle PQR and triangle P′Q′R′

If a figure dilated by factor k about the origin then

$(x,y)\rightarrow (kx,ky)$

PQR dilated by a scale factor of 3, so

$(x,y)\rightarrow (3x,3y)$

Using this rule we get

$P(3,-6)\rightarrow P'(3(3),3(-6))=P'(9,-18)$

$Q(6,-9)\rightarrow Q'(3(6),3(-9))=Q'(18,-27)$

$R(-15,3)\rightarrow R'(3(-15),3(3))=R'(-45,9)$

The vertices of image are P'(9,-18), Q'(18,-27) and R'(-45,9).

Therefore, the correct option is C.

6 0

2 years ago

Tarun has 4 more than the twice the number of tshirts Deepak has.Mahesh has 2 more than thrice the number of T-shirts that Tarun

Dafna11 [192]

Answer:

Deepak: 4 t-shirts,

Tarun: 12 t-shirts,

Mahesh: 14 t-shirts.

Step-by-step explanation:

Let x represent number of t-shirts that Deepak has.

Please consider the complete question.

Tarun has 4 t-shirt more than twice the number of T-shirts Deepak has. Mahesh has 2 more than thrice the number of T-shirts Deepak has. If the ratio of the t-shirt that Tarun and Mahesh have is 6 : 7, find out the number of the t-shirt each of them has.

Since Tarun has 4 t-shirt more than twice the number of T-shirts Deepak has, so the number of t-shirts that Tarun has would be $2x+4$ .

We are also told that Mahesh has 2 more than thrice the number of T-shirts Deepak has. So the number of t-shirts that Mahesh has would be $3x+2$ .

Since the ratio of the t-shirt that Tarun and Mahesh have is 6 : 7, so we can represent this information in an equation as:

$\frac{2x+4}{3x+2}=\frac{6}{7}$

Cross multiply:

$6(3x+2)=7(2x+4)$

$18x+12=14x+28$

$18x-14x+12-12=14x-14x+28-12$

$4x=16$

$x=\frac{16}{4}=4$

Therefore, Deepak has 4 t-shirts.

The number of t-shirts that Tarun has would be $2x+4\Rightarrow 2(4)+4=4+4=12$

Therefore, Tarun has 12 t-shirts.

The number of t-shirts that Mahesh has would be $3x+2\Rightarrow 3(4)+2=12+2=14$

Therefore, Mahesh has 14 t-shirts.

5 0

2 years ago

Given: ΔABC, AC = BC, AB = 3 CD ⊥ AB, CD = √3 Find: AC

valina [46]

Answer:

$\boxed{AC = 2.3}$

Step-by-step explanation:

AD = BD (CD bisects AB means that it divides the line into two equal parts)

So,

AD = BD = AB/2

So,

AD = 3/2

AD = 1.5

<u><em>Now, Finding AC using Pythagorean Theorem:</em></u>

$c^2 = a^2+b^2$

Where c is hypotenuse (AC), a is base (AD) and b is perpendicular (CD)

$AC^2= (1.5)^2+(\sqrt{3} )^2$

$AC^2 = 2.25 + 3$

$AC^2 = 5.25$

Taking sqrt on both sides

$AC = 2.3$

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2 years ago

What is the unit rate of 3 accidents in 12 months

Wewaii [24]

Simplify 3 to 12 Divide 3 1 to 4 So the answer is 1 car accident in 4 month ~JZ Hope it helps you out there

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