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pychu [463]
2 years ago
7

Omari and daisy live on my he same street as their school. Omari lives 3 1/2 blocks west of the school and daisy lives 3 1/4 blo

cks east of the school how far apart do omari and daisy live from eachother
Mathematics
1 answer:
OLEGan [10]2 years ago
5 0
Omari (3 1/2)___________(0)school____________(3 1/4)daisy

3 1/2 + 3 1/4 = 6 + (1/2 + 1/4) = 6 + (2/4 + 1/4) = 6 3/4 blocks apart <==


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Children under 10 years and older people over 65 years receive a discount on movie tickets. Let x represent the age of a person
mr_godi [17]

0<x<10

x>65

0<x<10 or x>65

4 0
2 years ago
Divide 794.1 by 7.61. Round off your answer to two decimal places. A. 104.35 B. 786.49 C. 95.83 D. 1,043.50
VikaD [51]
Answer: 
A. 104.35

Explanation: 
794.1 ÷ 7.61 = 104.34954 
Round off to two decimal places: 
104.349 
round 4 up to 5 because the next number is greater than 5: 
9 > 5 
So 
104.35
3 0
2 years ago
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In the following questions, look at different ways to represent the relation given by the equation y = x2 - 1. The table below s
Verdich [7]

Question: In the following questions, look at different ways to represent the relation given by the equation y = x2 - 1. The table below shows some values for the given equation. Find the values of a and b.

Answer:

a= 3

b= 0

4 0
2 years ago
Find the interest due to the bank on a loan of $1000 at 7.5% for 280 days
Lera25 [3.4K]

Answer:

The interest is \$57.53

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=280/365\ years\\ P=\$1.000\\r=0.075

substitute in the formula above

I=\$1.000(0.075*280/365)

I=\$57.53

7 0
2 years ago
A customer borrowed $2000 and then a further $1000 both repayable in 12 months. What should he have saved if he had taken out on
Neporo4naja [7]

Answer:

a. $60

Step-by-step explanation:  

We will use simple interest formula to solve our given problem.

A=P(1+rt), where

A= Amount after t years.

P= Principal amount.

r= Interest rate in decimal form.      

t= Time in years.

Let us find amount of loans repayable after 12 months for taking two amounts of $2000 and $1000.

As $2000 and $1000 are less than 2500, so the rate of loan will be 10%.

10\%=\frac{10}{100}=0.10

12 months = 1 year.

A=2000(1+0.10\times 1)

A=2000(1+0.10)

A=2000(1.10)

A=2200

Now let us find amount repayable after 12 months for borrowing $1000.

A=1000(1+0.10\times 1)

A=1000(1+0.10)

A=1000(1.10)

A=1100

Adding these amounts we will get total repayable amount after 12 months for borrowing $2000 and $1000 separately.

\text{Amount repayable for borrowing two separate amounts}=2200+1100=3300

Now let us find repayable amount after 12 months for taking 1 loan. As $3000 is between $2501 and $7500, so rate of loan will be 8%.

8\%=\frac{8}{100}=0.08

A=3000(1+0.08\times 1)

A=3000(1+0.08)

A=3000(1.08)

A=3240

Now let us find difference between both repayable loan amounts.

\text{Difference between both repayable loan amounts}=3300-3240

\text{Difference between both repayable loan amounts}=60

Therefore, the customer should have saved $60, if he had taken out one loan for $3000 and option a is the correct choice.

6 0
2 years ago
Read 2 more answers
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