Ask question

Ask question

All categories

2 years ago

7

Omari and daisy live on my he same street as their school. Omari lives 3 1/2 blocks west of the school and daisy lives 3 1/4 blo

cks east of the school how far apart do omari and daisy live from eachother

1 answer:

OLEGan [10]2 years ago

5 0

Omari (3 1/2)___________(0)school____________(3 1/4)daisy

3 1/2 + 3 1/4 = 6 + (1/2 + 1/4) = 6 + (2/4 + 1/4) = 6 3/4 blocks apart <==

You might be interested in

Children under 10 years and older people over 65 years receive a discount on movie tickets. Let x represent the age of a person

mr_godi [17]

0<x<10

x>65

0<x<10 or x>65

4 0

2 years ago

Divide 794.1 by 7.61. Round off your answer to two decimal places. A. 104.35 B. 786.49 C. 95.83 D. 1,043.50

VikaD [51]

Answer:
A. 104.35

Explanation:
794.1 ÷ 7.61 = 104.34954
Round off to two decimal places:
104.349
round 4 up to 5 because the next number is greater than 5:
9 > 5
So
104.35

3 0

2 years ago

Read 2 more answers

In the following questions, look at different ways to represent the relation given by the equation y = x2 - 1. The table below s

Verdich [7]

Question: In the following questions, look at different ways to represent the relation given by the equation y = x2 - 1. The table below shows some values for the given equation. Find the values of a and b.

Answer:

a= 3

b= 0

4 0

2 years ago

Find the interest due to the bank on a loan of $1000 at 7.5% for 280 days

Lera25 [3.4K]

Answer:

The interest is $\$57.53$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=280/365\ years\\ P=\$1.000\\r=0.075$

substitute in the formula above

$I=\$1.000(0.075*280/365)$

$I=\$57.53$

7 0

2 years ago

A customer borrowed $2000 and then a further $1000 both repayable in 12 months. What should he have saved if he had taken out on

Neporo4naja [7]

Answer:

a. $60

Step-by-step explanation:

We will use simple interest formula to solve our given problem.

$A=P(1+rt)$ , where

A= Amount after t years.

P= Principal amount.

r= Interest rate in decimal form.

t= Time in years.

Let us find amount of loans repayable after 12 months for taking two amounts of $2000 and $1000.

As $2000 and $1000 are less than 2500, so the rate of loan will be 10%.

$10\%=\frac{10}{100}=0.10$

12 months = 1 year.

$A=2000(1+0.10\times 1)$

$A=2000(1+0.10)$

$A=2000(1.10)$

$A=2200$

Now let us find amount repayable after 12 months for borrowing $1000.

$A=1000(1+0.10\times 1)$

$A=1000(1+0.10)$

$A=1000(1.10)$

$A=1100$

Adding these amounts we will get total repayable amount after 12 months for borrowing $2000 and $1000 separately.

$\text{Amount repayable for borrowing two separate amounts}=2200+1100=3300$

Now let us find repayable amount after 12 months for taking 1 loan. As $3000 is between $2501 and $7500, so rate of loan will be 8%.

$8\%=\frac{8}{100}=0.08$

$A=3000(1+0.08\times 1)$

$A=3000(1+0.08)$

$A=3000(1.08)$

$A=3240$

Now let us find difference between both repayable loan amounts.

$\text{Difference between both repayable loan amounts}=3300-3240$

$\text{Difference between both repayable loan amounts}=60$

Therefore, the customer should have saved $60, if he had taken out one loan for $3000 and option a is the correct choice.

6 0

2 years ago

Read 2 more answers