Answer:
a.0.8664
b. 0.23753
c. 0.15866
Step-by-step explanation:
The comptroller takes a random sample of 36 of the account balances and calculates the standard deviation to be N42.00. If the actual mean (1) of the account balances is N175.00, what is the probability that the sample mean would be between
a. N164.50 and N185.50?
b. greater than N180.00?
c. less than N168.00?
We solve the above question using z score formula
z = (x-μ)/σ/√n where
x is the raw score,
μ is the population mean = N175
σ is the population standard deviation = N42
n is random number of sample = 36
a. Between N164.50 and N185.50?
For x = N 164.50
z = 164.50 - 175/42 /√36
z = -1.5
Probability value from Z-Table:
P(x = 164.50) = 0.066807
For x = N185.50
z = 185.50 - 175/42 /√36
z =1.5
Probability value from Z-Table:
P(x=185.50) = 0.93319
Hence:
P(x = 185.50) - P(x =164.50)
= 0.93319 - 0.066807
= 0.866383
Approximately = 0.8664
b. greater than N180.00?
x > N 180
Hence:
z = 180 - 175/42 /√36
z = 5/42/6
z = 5/7
= 0.71429
Probability value from Z-Table:
P(x<180) = 0.76247
P(x>180) = 1 - P(x<180) = 0.23753
c. less than N168.00?
x < N168.
z = 168 - 175/42 /√36
z = -7/42/6
z = -7/7
z = -1
Probability value from Z-Table:
P(x<168) = 0.15866
the ratio in which 42 should be divided is 1:2:3
the sum of the parts of the ratio is - 1 + 2 + 3 = 6
this means that there's a sum of 6 parts
so we need to find how much 1 part is equivalent to
if 6 parts are equivalent to 42
then 1 part is equivalent to - 42/6 = 7
so the ratio should be 1:2:3
1 part - 7
2 parts - 7 x 2 = 14
3 parts - 7 x 3 = 21
therefore 42 divided into 1:2:3 ratio is as follows
7 : 14 : 12
<span>You are asked to draw circle O with radius 12. Then draw radii OA and OB to form an angle with the measure named. You are asked to find the length of AB. The answers for each of the following measures are:
1)Measure of AOB=90, AB = 16.97 units
2)measure of AOB=180, AB = 24 units
3) measure of AOB=60, AB = 10.39 units
3) measure of AOB=120, AB = 10.39 units</span>
Let x represent gallons of $19 paint
let y represent gallons of $3 paint
first you make your 2 equations
x+y=16, y=16-x
(19x+3y) ÷ 16 = 14
then you use substitution
14 = (19x + 3(16-x) ) ÷16
224 = 19x + 48 - 3x
176 = 16x
11 = x, so there's 11 gallons of $19 paint
recall that x+y=16
11+y=16
5=y
so there are 11 gallons of $19 paint and 5 gallons of $3 paint
Answer:
81%
Step-by-step explanation:
Let 'L' be the dominant and 'l' e the recessive allele for ‘lazybuttness’.
Since ‘lazybuttness’ is an autosomal dominant condition, the 19% of students affected by the condition correspond to the homozygous dominant (LL) and heterozygous (Ll) genotypes. Therefore, the rest of the population has the homozygous recessive genotype (ll) and is not affected. The frequency of students not affected is:
F = 100% - 19% = 81%
