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1 year ago

A collection of 77 quarters and dimes is worth $12.50. How many quarters and dimes are there? Set it up plz

1 answer:

mihalych1998 [28]1 year ago

4 0

So let's say quarters = x and dimes = y. You'd then put x + y = 77 (for a total of 77 coins). And your second equation would be .25x + .10y = 12.50 (.25 for the total value a quarter holds and .10 for a total value a dime holds). Then you'd do matrices on a calculator.

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If four is half of five and two thirds of six is nine. what is thirty-two?

valkas [14]

Four is IV which is half of five. IX is nine which is 2 thirds of 6 so... thirty-two is 1 5/6

5 0

1 year ago

2 1/3 −1.5x=12.3 please help me I'm really struggling need an answer ASAP.

Harrizon [31]

Answer:

-6.64

Step-by-step explanation:

since you need to find the value of x , but all values to one side and have x on the other .. meaning :

2 1/3 -12.3 = 1.5x

now that you have this find the decimal value of 2 1/3

which is 2*3 +1 = 7/3

in decimal form is 2.33333...

now subtract (2.3333.. - 12.3 ) / 1.5

x = -6.6444

to 3 sf = -6.64

7 0

1 year ago

Jacobs sand bucket has a top diameter of 10 inches and a bottom diameter of 7 inches. the bucket is 12 inches tall. What’s the v

Elanso [62]

We know that
The volume of a circular truncated cone=(1/3)*pi*[r1²+r1*r2+r2²]*h
where
r1=7/2-----> 3.5 in
r2=10/2----> 5 in
h=12 in
volume of a circular truncated cone=(1/3)*pi*[3.5²+3.5*5+5²]*12
volume=688 in³

the answer is
688 in³

4 0

1 year ago

The number of cities in a region over time is represented by the function C(x)=2.9(1.05)^x. The approximate number of people per

N76 [4]

Answer:

B. $T(x) = 2.9\cdot (1.05)^{4\cdot x + 5}$

Step-by-step explanation:

The approximate population in the region is the product of the number of cities in a region and the approximate number of people per city, that is:

$T(x) = C(x)\cdot P(x)$ (1)

If we know that $C(x) = 2.9\cdot (1.05)^{x}$ and $P(x) = (1.05)^{3\cdot x + 5}$ , then the formula for the approximate population in the region is:

$T(x) = [2.9\cdot (1.05)^{x}]\cdot [(1.05)^{3\cdot x + 5}]$

$T(x) = 2.9\cdot (1.05)^{4\cdot x + 5}$

Hence, correct answer is B.

3 0

1 year ago

In a data set with a range of 55.4 to 105.4 and 400 observations, there are 176 observations with values less than 86. Find the

IrinaVladis [17]

<u>ANSWER: </u>

In a data set with a range of 55.4 to 105.4 and 400 observations.86 lies in the 49th percentile.

<u>SOLUTION: </u>

Given, in a data set with a range of 55.4 to 105.4 and 400 observations.

There are 176 observations below the value of 86, and we need to find the percentile for 86.

We know that, percentile formula = $\frac{\text {number of observations below the required number}}{\text {total number of observations}} \times 100$

Percentile of 86 = $\frac{176}{400} \times 100$

Since, we cancelled 400 with 100 we get 4 , hence above expression becomes,

$=\frac{176}{4}$ = 49

So, percentile of 86 = 49

Hence, 86 lies in the 49th percentile.

5 0

1 year ago