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Rom4ik [11]
2 years ago
12

If dB=4 and dc=6 find ad

Mathematics
2 answers:
Neporo4naja [7]2 years ago
7 0
See the attached figure
DB = 4 and DC = 6 , We need to find AD

Using <span>Euclid's theorem for the right triangle
</span><span>
</span><span>∴ DB² = AD * DC
</span><span>
</span><span>∴ 4² = AD * 6
</span><span>
</span><span>∴ 6 AD = 16
</span><span>
</span><span>
</span><span>∴ AD = 16/6 = 8/3 ≈ 2.67
</span>

ikadub [295]2 years ago
5 0

Answer:

AD=2,667

Step-by-step explanation:

Given that ABC is a right triangle, right angled at B

BD is the altitude

Since DB and DC are given we can find tan c using right triangle BCD

tan c = \frac{DB}{DC} =\frac{4}{6}

Angle ABD is complement of angle A

In triangle ABC , C is complement of angle A

Hence C = angle ABD

tan ABD = tan C =\frac{AD}{DB} =\frac{AD}{4}

Simplify to get

AD = 4tanC=4(\frac{4}{6} )\\=\frac{8}{3}

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2 years ago
Casey needed to move 23 huge boxes from his truck to the loading dock. His forklift could only hold three boxes at once. How man
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Answer:

8

Step-by-step explanation:

Since the forklift has a maximum capacity of three boxes per trip, simply divide the total number of boxes (23 boxes) by three and round up to the nearest whole unit to find the number of trips required:

n=\frac{23}{3}=7.667

Casey had to visit the dock 8 times. He moved three boxes in seven trips and two boxes in one trip.

6 0
2 years ago
Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
2 years ago
Madison starts with a population of 1,000 amoebas that triples in size every hour for a number of hours, h. She writes the expre
gtnhenbr [62]

Answer: The meaning of each term of the  Madison’s and Tyler’s expressions is mentioned below.

Step-by-step explanation:

Since, when Madison starts with a population of 1,000 amoebas that triples in size every hour for a number of hours, h.

That is, after 1 hour total number of amoebas = 3×1000 = 3^1\times 1000

After 2 hour,  total number of amoebas = 3×3000=3^2\times 100

After 3 hour, total number of amoebas = 3×9000= 3^3\times 1000

similarly, after h hours, total number of amoebas,

f(h) = 3^h\times 1000

where, 1000 is the initial population of amoeba 3 is the growth factor of population and f(h) is the population of amoeba after h hours.

Since, when Tyler starts with a population of 1 amoeba that  increases 30% in size every hour for a number of hours.

That is, after 1 hour total number of amoebas = (1+0.3)^1

After 2 hour,  total number of amoebas =  (1+0.3)^2

After 3 hour, total number of amoebas =  (1+0.3)^3

Similarly, after h hours, total number of amoebas,

f(h) =(1+0.3)^h

Where,  1 is the initial population of amoeba, 0.3 is the growth rate and 1.3 is the growth factor.


5 0
2 years ago
Read 2 more answers
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