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2 years ago

Find the height of a baseball with a mass of 0.15 kg that has a GPE of 73.5 J. Help please?

Physics

2 answers:

LUCKY_DIMON [66]2 years ago

8 0

Hight is 50 b/c it is on the ledt side

Slav-nsk [51]2 years ago

4 0

Gravitational Potential Energy of an object, relative to the ground =

   (mass) x (acceleration of gravity) x (height above the ground)

   73.5 J = (0.15 kg) x (9.8 m/s²) x (height above the ground).

1 J = 1 kg · m² / s²

   73.5 kg·m²/s² = (0.15 kg) · (9.8 m/s²) · (height)

Divide each side by (0.15 kg):

   (73.5 kg·m² / (0.15 kg·s²) = (9.8 m/s²) · (height)

Divide each side by (9.8 m/s²):

   (73.5 kg·m²·s²) / (0.15 kg·s² · 9.8 m) = (height)

After doing all the arithmetic on the left side:

   (73.5) / (0.15 · 9.8) (m)   =   height

   50 (m)    =   height

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You and your family take a trip to see your aunt who lives 100 miles away along a straight highway. The first 60 miles of the tr

Nitella [24]

Answer:

51.2 mi/h

Explanation:

Total distance, d = 100 miles

First 60 miles with speed 55 mi/h

Next 40 miles with speed 75 mi/h

Time taken for first 60 miles, t1 = 60 / 55 = 1.09 h

Time taken for 40 miles, t2 = 40 / 75 = 0.533 h

Time spent to get stuck, t3 = 20 min = 0.33 h

Total time, t = t1 + t2 + t3 = 1.09 + 0.533 + 0.33 = 1.953 h

The average speed is defined as the ratio of total distance traveled to the total time taken.

Average speed = $=\frac{100}{1.953}=51.2 mi/h$

Thus, the average speed of the journey is 51.2 mi/h.

4 0

2 years ago

Determine the specific volume of refrigerant-134a at 1 MPa and 50°C, using (a) the ideal-gas equation of state and (b) the gener

Andrej [43]

Answer:

( a ) The specific volume by ideal gas equation = 0.02632 $\frac{m^{3} }{kg}$

% Error = 20.75 %

(b) The value of specific volume From the generalized compressibility chart = 0.0142 $\frac{m^{3} }{kg}$

% Error = - 34.85 %

Explanation:

Pressure = 1 M pa

Temperature = 50 °c = 323 K

Gas constant ( R ) for refrigerant = 81.49 $\frac{J}{kg k}$

(a). From ideal gas equation P V = m R T ---------- (1)

⇒ $\frac{V}{m}$ = $\frac{R T}{P}$

⇒ Here $\frac{V}{m}$ = Specific volume = v

⇒ v = $\frac{R T}{P}$

Put all the values in the above formula we get

⇒ v = $\frac{323}{10^{6} }$ ×81.49

⇒ v = 0.02632 $\frac{m^{3} }{kg}$

This is the specific volume by ideal gas equation.

Actual value = 0.021796 $\frac{m^{3} }{kg}$

Error = 0.02632 - 0.021796 = 0.004524 $\frac{m^{3} }{kg}$

% Error = $\frac{0.004524}{0.021796}$ × 100

% Error = 20.75 %

(b). From the generalized compressibility chart the value of specific volume

$\frac{V}{m}$ = v = 0.0142 $\frac{m^{3} }{kg}$

The actual value = 0.021796 $\frac{m^{3} }{kg}$

Error = 0.0142 - 0.021796 = $\frac{m^{3} }{kg}$

% Error = $\frac{- 0.0076}{0.021796}$ × 100

% Error = - 34.85 %

3 0

2 years ago

How much power does it take to lift a 24 kg gift box 6m above the floor in 4 s?

Mrac [35]

Answer:

Explanation:

Step one:

given

mass m= 24kg

distance moved= 6m

time taken= 4seconds

Step two:

Required

power

but work done is the force applied at a distance, and the power is the work done time the time taken

Work done= F*D

F=mg

W= mg*D

W=24*9.81*6

W=1412.6J

Power P= work * time

P=1412.6*4

p=5650.5W

P=5.6kW

3 0

2 years ago

A photon with a wavelength of 2.29 × 10^–7 meter strikes a mercury atom in the ground state.

4vir4ik [10]

The photon can be absorbed and the energy of the photon is exactly equal to the energy-level difference between the ground state and the level d.

8 0

2 years ago

A straight wire carries a current of 3 A which is in the plane of this page, pointed toward the top of the page. A particle of c

Ilia_Sergeevich [38]

Answer:

The magnitude of the magnetic force exerted on the moving charge by the current in the wire is 2.18 x $10^{-8}$ N

The direction of the magnetic force exerted on the moving charge by the current in the wire is radially inward

Explanation:

given information:

current, I = 3 A

$q_{0}$ = +6.5 x $10^{-6}$ C

r = 0.05 m

v = 280 m/s

and direction of the magnetic force exerted on the moving charge by the current in the wire, we can use the following formula:

F = qvB sin θ

where

F = magnetic force (N)

q = electric charge (C)

v = velocity (m/s)

θ = the angle between the velocity and magnetic field

to find B we use

B = μ $_{0}$ I/2πr

μ $_{0}$ = 4π x $10^{-7}$ or 1.26 x $10^{-6}$ N/ $A^{2}$ , thus

B = 4π x $10^{-7}$ x 3 / 2π(0.05)

= 1.2 x $10^{-5}$ T

Now, we can calculate the magnitude force

F = qvB sin θ

θ = 90°, because the speed and magnetic are perpendicular

F = 6.5 x $10^{-6}$ x 280 x 1.2 x $10^{-5}$ sin 90°

= 2.18 x $10^{-8}$ N

Using the hand law, the magnetic direction is radially inward

8 0

2 years ago