Answer:
a) r=4.24cm d=1 cm
b) 
Explanation:
The capacitance depends only of the geometry of the capacitor so to design in this case knowing the Voltage and the electric field
The distance must be the separation the r distance can be find also using
But now don't know the charge these plates can hold yet so
a).
d=0.01m
b).
Answer:
0.266 m
Explanation:
Assuming the lump of patty is 3 Kg then applying the principal of conservation of linear momentum,
P= mv where p is momentum, m is mass and v is the speed of an object. In this case
where sunscripts p and b represent putty and block respectively, c is common velocity.
Substituting the given values then
3*8=v(15+3)
V=24/18=1.33 m/s
The resultant kinetic energy is transferred to spring hence we apply the law of conservation of energy
where k is spring constant and x is the compression of spring. Substituting the given values then
Answer:
<h2>a)
Nathan's acceleration is 5 m/s²
</h2><h2>b)
Nathan's displacement during this time interval is 15.625 m</h2><h2>
c) Nathan's average velocity during this time interval is 6.25 m/s</h2>
Explanation:
a) We have equation of motion v = u + at
Initial velocity, u = 0 m/s
Final velocity, v = 12.5 m/s
Time, t = 2.5 s
Substituting
v = u + at
1.25 = 0 + a x 2.5
a = 5 m/s²
Nathan's acceleration is 5 m/s²
b) We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 5 m/s²
Time, t = 2.5 s
Substituting
s = ut + 0.5 at²
s = 0 x 2.5 + 0.5 x 5 x 2.5²
s = 15.625 m
Nathan's displacement during this time interval is 15.625 m
c) Displacement = 15.625 m
Time = 2.5 s
We have
Displacement = Time x Average velocity
15.625 = 2.5 x Average velocity
Average velocity = 6.25 m/s
Nathan's average velocity during this time interval is 6.25 m/s
If i remeber correctly when dealing with real world cordinate systems as you rotate around clockwise you move in a positive direction. but all the examples i have done said north was 0 degrees, so i may be wrong
